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olga nikolaevna [1]
3 years ago
12

Find the area. Answer ASAP pls pls

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

This is your answer ☺️

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pretty sure its growth

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2 years ago
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You have 15 pennies in your pocket. Of those pennies, 3 are Canadian. Suppose you pick a penny out of your pocket at random. Fin
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12 out of 15. 12/15 = 4/5 answer is b
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What is 8 x 10 power of 0
Lapatulllka [165]

Question:- Find

8 \times  {10}^{0}

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{10}^{0}  = 1

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8 \times  {10}^{0}  \\ 8 \times 1  \\ 8 \: ans

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How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

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2 years ago
The sum of the measures of the two angles of a linear pair must be
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Answer:  180

Angles in a linear pair are always supplementary. This means they form a straight angle or a straight line.

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