Question

Can someone solve these for me? its factoring trinomials

Answer 1

Answer:

1.) $\left(x-3\right)\left(x+6\right)$

2.) $\left(a-3\right)^2$

3.) $=\left(t+8\right)\left(t-9\right)$

4.) $=\left(b+7\right)^2$

Step-by-step explanation:

2.) $=a^2-2a\cdot \:3+3^2$, $\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$.

$a=a,\:b=3$

$=\left(a-3\right)^2$

3.) $=\left(t^2+8t\right)+\left(-9t-72\right)$$=t\left(t+8\right)-9\left(t+8\right)$, $\mathrm{Factor\:out\:common\:term\:}t+8$.

$=\left(t+8\right)\left(t-9\right)$