What is the solution set of 7x^2 + 3x = 0? A. {0, 3/7} B. {0, -3/7} C. {0, -4/7}

2 answers:

6 0

To solve the solution set of the problem, we can factor the expression given into x* ( 7x + 3 ) = 0. This dissects the equation into two parts:
x = 0
and
7x + 3 = 0x = -3/7
Hence the answer to this problem must be B. {0, -3/7}

Oksana_A [137]3 years ago

3 0

7x² + 3x = 0

x(7x + 3) = 0 ⇔ x = 0 or 7x + 3 = 0 |subtract 3 from both sides

x = 0 or 7x = -3 |divide both sides by 7

x = 0 or x = - 3/7

Answer: B. {0; -3/7}

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Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

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$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

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Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

2 years ago

Jim

stealth61 [152]

yes i agree because if all the integers are positive, the answer stays positive which means if you know your integer rules: a positive divide by a positive it stays positive. its the same thing for all the other operations. hope this helps.

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3 years ago

Read 2 more answers

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