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Romashka-Z-Leto [24]
3 years ago
10

A culture started with 2,000 bacteria. After 8 hours, it grew to 2,400 bacteria. Predict how many bacteria will be present after

19 hours. Round your answer to the nearest whole number.
Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

2950 [Starting from 2,000 bacteria.]

Step-by-step explanation:

400/8 = 50

Bacteria grown/time = bacteria per hour

19x50 = 950

time x bacteria per hour = bacteria grown

2000 + 950

bacteria started + bacteria grown

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D. at least two girls
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dexamethasone 4 mg/1 ml is available. the MD orders 6000 mcg. how much will the nurse give? (Round to the tenth)​
aleksley [76]

Answer:

  1.5 mL

Step-by-step explanation:

The abbreviation mcg stands for "microgram," or 10^-6 grams. The abbreviation mg stands for "milligram," or 10^-3 grams. The relationship between these is ...

  1 mg = 1000 mcg

<h3>Dose</h3>

The order for 6000 mcg is an order for 6(1000 mcg) = 6(1 mg) = 6 mg. At 4 mg/mL, the quantity of dexamethasone required is ...

  (6 mg)/(4 mg/mL) = (6/4) mL = 1.5 mL

The nurse will give 1.5 milliliters of dexamethasone.

4 0
2 years ago
The side lengths of four triangles are listed below. Determine whether each triangle is a right triangle Choose Yes or No for ea
Ira Lisetskai [31]

Answer:

yes, yes, no, no

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i
nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

A = \frac{1}{2}\cdot b\cdot h (Eq. 1)

Where:

A - Area of the triangle, measured in square centimeters.

b - Base of the triangle, measured in centimeters.

h - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA}{dt} - Rate of change of area in time, measured in square centimeters per minute.

\frac{db}{dt} - Rate of change of base in time, measured in centimeters per minute.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

\frac{1}{2}\cdot\frac{db}{dt}\cdot h =  \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}

\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt} (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

b = \frac{2\cdot A}{h}

If we know that A = 130\,cm^{2}, h = 15\,cm, \frac{dh}{dt} = 2.5\,\frac{cm}{min} and \frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}, the rate of change of the base of the triangle in time is:

b = \frac{2\cdot (130\,cm^{2})}{15\,cm}

b = 17.333\,cm

\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)

\frac{db}{dt} = -2.262\,\frac{cm}{min}

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0
3 years ago
Simplfy 1/4 (q-16)+1/3(q+12)
ValentinkaMS [17]

Answer:

7q is the numerator which is the top and the denominator is 12 which is the bottom number.

Step-by-step explanation:

4 0
2 years ago
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