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2 years ago

I GIVE BRAINIEST Can someone help me with this pls

Mathematics

1 answer:

Juliette [100K]2 years ago

5 0

Answer:

A. moving forward for 10m at a steady pace of 2m/s

B. moving backwards 8m at a steady pace of 2.67m/s

C. staying in the same spot for 4 seconds

D. moving 9m at a steady pace of 4.5m/s

E. moving 4.5m with an average pace of 1.5m/s

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Bananas cost 0.59 per pound. Create an equation that could be used to find the total cost of y of x bananas

n200080 [17]

Answer:

y = 0.59x

Step-by-step explanation:

Cost per pound of banana = $0.59

If Number of banana's = x

Total Cost of an item = price per item * number of items

Therefore,

Total cost, y = price per pound of banana * number of bananas

y = 0.59 * x

y = 0.59x

8 0

2 years ago

What is the distance between -12 and 15?

motikmotik

Answer:

Step-by-step explanation:

to get the distance, add -12 and 15 which gets you 27

8 0

2 years ago

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The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the

stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

$f'(t)=2000-12t^{2}$

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (t = 0) to 2000 (t = 10) as follows:

$\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000$

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

$=40000+16000\\=56000$

Thus, the worth of the company in 2000 is $56,000.

4 0

3 years ago

Suppose a population of honey bees in Ephraim, UT has an initial population of 2300 and 12 years later the population reaches 13

Rama09 [41]

Answer:

common ratio: 1.155

rate of growth: 15.5 %

Step-by-step explanation:

The model for exponential growth of population P looks like: $P(t)=P_i(1+r)^t$

where $P(t)$ is the population at time "t",

$P_i$ is the initial (starting) population

$(1+r)$ is the common ratio,

and $r$ is the rate of growth

Therefore, in our case we can replace specific values in this expression (including population after 12 years, and initial population), and solve for the unknown common ratio and its related rate of growth:

$P(t)=P_i(1+r)^t\\13000=2300*(1+r)^{12}\\\frac{13000}{2300} = (1+r)^12\\\frac{130}{23} = (1+r)^{12}\\1+r=\sqrt[12]{\frac{130}{23} } =1.155273\\$

This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155

We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

$1+r=1.155273\\r=1.155273-1=0.155273$

So, this number in percent form (and rounded to the nearest tenth as requested) is: 15.5 %

6 0

2 years ago

PLEASE HELP ME SOLVE THIS, WHOEVER DOES WILL EARN 100 PTS!!!!!!!!!!!!!

Monica [59]

Step-by-step explanation:

(Assuming that this triangle is isosceles)

If this triangle is isosceles, then x° is going to be equal to its twin angle; 40°.

We can solve for z now.

180 = 40 + 40 + z

180 = 80 + z

Subtract 80 from both sides.

100 = z

z = 100°

Now that we know z = 100 degrees, we can begin to solve the expression (3x -20)

The expression sits on a 180° line and the angle z (100°) shares the line with the expression (3x - 20)°

180 = 100 + (3x - 20)

Subtract 100 from both sides.

80 = 3x - 20

Add 20 to both sides to isolate 3x

100 = 3x

Divide by 3 on both sides.

100/3 = 3x/3

33.33... = x

4 0

3 years ago

Read 2 more answers