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marin [14]
3 years ago
12

Construct the line perpendicular to ⇒NO at point P.

Mathematics
2 answers:
suter [353]3 years ago
7 0
The 3rd one is correct, you would put a compass on Point P and draw a small arc on lIne NO on each side of Point P, then place the compass on the line at those points and draw arcs above and below P then connect those points with a ruler.
shepuryov [24]3 years ago
4 0

Answer:

The third one.

Step-by-step explanation:

Basic style of how you construct a perpendicular bisector.

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The height of five soldiers included 60inches,67inches,65inches and 64inches,if the mean of the five soldiers is 65inches what i
Nadya [2.5K]

Answer:

The last guy's height is 69 inches

Step-by-step explanation:

mean=sum of all numbers/number of numbers

There are 5 numbers in the set which means that 65 is the sum of all five numbers divided by 5. To reverse that we multiply 65 by 5 to get the sum of all of the numbers.

65*5=325

325 is the sum of all of the numbers so to find the missing number you add up all of the known numbers in the set and find the difference between that sum and 325.

60+67+65+64=256

325-256=69

The missing guy's height is 69 inches.

3 0
3 years ago
Find the measure of a 6.<br> 102<br> 78<br> 46 = [?]
Rom4ik [11]

Answer:

102°

Step-by-step explanation:

They're still corresponding angles... have you read any of these explanations?...

6 0
3 years ago
Hiro bought a small carton of milk at lunch. If the approximate dimensions of the milk carton are shown what is the minimum amou
faltersainse [42]

Answer:

C.\ 104\ in^2

Step-by-step explanation:

At first, the question looks like an optimization problem, but since all the dimensions of the carton are given, we only have to compute the total area of the given figure.

Let's calculate the front (and back) areas, which are rectangles

A_1=(6.5)(3)=19.5\ in^2

Now with the lateral rectangles which happen to have the very same dimensions

A_2=19.5\ in^2

Next, we compute the front and back triangles of base 3 in and height 1.5 in

A_3=\frac{1}{2}(3)(1.5)=2.25\ in^2

Now, the lateral inclined rectangles of base 3 in and height 2 in

A_4=(3)(2)=6\ in^2

Finally, the base rectangle who happens to be a square of side 3 in

A_5=(3)(3)= 9\ in^2

This last area, unlike all others, is not doubled because its counterpart is inside the carton and is not part of the lateral area

Our total area of cardboard is

A_t=2(19.5)+2(19.5)+2(2.25)+2(6)+9=103.5\ in^2

The closest option to this answer is

C.\ 104\ in^2

5 0
3 years ago
Read 2 more answers
(question is on picture linked)
nalin [4]

here y+13=15

so we got y=2

then y+13+x+12=30

then we will get x=3

7 0
3 years ago
Please answer this question, thx :)
dusya [7]

Answer:

49.5

Step-by-step explanation:

just put into you calculator

47+(15/3)/2

3 0
3 years ago
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