20I%27m%20%20%5C%3A%20desperate%20%20-%20.%20-%20%20%7D" id="TexFormula1" title=" \sf \red{Help \: help \: help \: help \: I'm \: desperate - . - }" alt=" \sf \red{Help \: help \: help \: help \: I'm \: desperate - . - }" align="absmiddle" class="latex-formula">
2 answers:
Answer:
1. x = 20
y = 120
2. x = 263
Step-by-step explanation:
•••
As AOB is a line,
( 7x - 20 ) + 3x = 180
7x - 20 + 3x = 180
10x - 20 = 180
10x = 180 + 20 = 200
10x = 200
x = 200/10 = 20
Then, as COD is a line,
y + 3x = 180
y + 3(20) = 180
y + 60 = 180
y = 180 - 60 = 120
•••
2. Draw a parallel line AB and CD.
Then,
Angle BAE + Angle y = 180 [Co-interior angles]
56 + y = 180
y = 180 - 56 = 124
Angle DCE + Angle z = 180
41 + z = 180
z = 180 - 41
z = 139
Now, z + y = 139 + 124 = 263
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Answer:
x= 2√37
Step-by-step explanation:
First thing you want to do is find the length of the missing side where the the right angle is at. You can find that with the pythagorean theorem of the other triangle, since you are already given 2 sides.
Pythagorean Theorem
a=2
b=?
c=2√2
Plug in and solve for b.
2^2+b^2=(2√2)^2
4+b^2=8
b^2=4
b=2
Now use the pythagorean theorem again to find your x side.
a=2
b=12
c=?
2^2+12^2=c^2
4+144=c^2
148=c^2
c=√148
c=2√37
