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never [62]
3 years ago
14

Does anyone know the answer to this?

Mathematics
1 answer:
denis23 [38]3 years ago
4 0

Answer:

g(x) = 3(x - 12)^{2} - 5

Step-by-step explanation:

Horizontal translations = f(x ± h)

Reflection over the x-axis = - f(x)

For the function f(x) = - 3(x - 4)^{2} +5, translating the parabola 8 units to the right means the horizontal shift of the graph, adding (- 8) to the <em>h</em> input.  This is represented by: g(x) = - 3(x - 12)^{2} +5.  

Next, flipping the graph over the x-axis represent a reflection. Since we currently have a negative coefficient for the value of <em>a</em>, then the opposite of a negative coefficient is a positive coefficient.

Therefore, the rightward horizontal translation of 8 units, and the reflection of the graph over the x-axis is represented by:

g(x) =  3(x - 12)^{2} - 5

For your reference, the three images below shows the transformations on the graph. The first image is the original function (in red parabola). The second image represents the reflection over the x-axis (green parabola). The third image shows the horizontal shift, 8 units to the right (blue parabola). If you take note of the varying values in vertices, (<em>h, k </em>) for the three graphs, you'll see that the original vertex was (4, 5) and the new vertices for the transformations are (4, -5) for the <u>reflection</u> and (12, -5) for the <u>shift</u>.

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Find x when : 3x^3 - 2x +1 = 0
notsponge [240]
Answer:  x = "-1 " ;  <u>and</u>:  "(1 ± √3) / 2" .
____________________________________________
Explanation:
____________________________________________
Given:  3x³ −  2x  + 1 = 0 ;  Find "x" ; 

Factor:  "3x³ −  2x + 1"  ;

3x³ − 2x + 1 = (3x² <span>− 3x + 1)(x + 1) ;

Now, set the equation equal to "0" (zero);

</span> (3x² − 3x + 1)(x + 1) = 0 ;

x = 0  ; when:
__________________________________
(x + 1) = 0 ;  and/or: when:

(3x² − 3x + 1) = 0 ;
__________________________________

Start with "x + 1 = 0" ;

Subtract "1" from each side of the equation ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ; 

              x + 1 − 1 = 0 − 1 ; 

                x = -1 ;

_______________________________
Now, try:  

3x² − 3x + 1 = 0 ;

Since:  "3x² − 3x + 1 " cannot be factored; and since:

  "3x² − 3x + 1 = 0" ; is written in the "quadratic equation format"; that is:

  "ax² + bx + c = 0 ;  a ≠ 0;  We can use the "quadratic equation formula" to solve for "x" ;  

in which "a = 3" ;   
              "b = -3" ;
              "c = 1" ;
     
The quadratic equation formula is:
__________________________________

x = [-b ± √(b²−4ac] / 2a ;

   = ?  (Let us plug in our known values for "a, b, & c"l 

x = { [-(-3] ± [√[(-3²) − (4*3*1)] } / {2* 3} ;

x = [3 ± √(9 − 12)] / 6 

x = [3 ± √(-3 )] / 6 ; 

x = (1 ± √3) / 2 .
<span>__________________________________________________
So, the answers are:  x = " -1 " ;  and:  "</span>(1 ± √3) / 2 " .
__________________________________________________
8 0
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