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Varvara68 [4.7K]
3 years ago
14

Help me out, if right get brainlest​

Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0

Answer:

PQN≈STR

Step-by-step explanation:

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7(3.5+2)+8(9.3-7) please help​
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Answer:

awdwdadadawdawdawdw

Step-by-step explanation:

awdadwdawddwadawdwa

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Plzzzzzzzz help for a brainly
alexandr402 [8]

Answer:

The first one is supplementary

The second one is complementary

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Step-by-step explanation:

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Solve the system of equations.
horrorfan [7]
The possible ordered pairs to solve this system are (8, 14) and (6, -12).

To solve this, use the second equation, which is already solved for y and put it in for y in the first equation. From that you will simplify and solve for 0 to get:

-x^2 + 14x - 48 = 0

Factor this and solve to get the possible x values as 8 and 6. Then use them in either equation to find the appropriate values for y. 
3 0
3 years ago
Describe Henry's location relative to the library.
Evgen [1.6K]

Answer:

Part 1)

Henry's location is at the ordered pair (-3,4)

Libray's location is at the ordered pair (2,-3)

Part 2) Henry is 5 city blocks at the left of the library and 7 city blocks up of the library

Step-by-step explanation:

Part 1) Write the ordered pairs that represent Henry and the Library

we have that

Henry's location is at the ordered pair (-3,4)

Libray's location is at the ordered pair (2,-3)

Part 2) Describe Henry's location relative to the library

Observing the graph  

Henry is 5 city blocks at the left of the library and 7 city blocks up of the library

4 0
3 years ago
From her eye, which stands 1.73 meters above the ground, London measures the angle of elevation to the top of a prominent skyscr
Airida [17]

The height of the skyscraper is 226.32 meters (rounded to the nearest hundredth of a meter)

An illustrative diagram is shown in the attachment below:

In the diagram, /TB/ is the height of the skyscraper

/BL/ is the horizontal distance from the base of the skyscraper to where London is standing

Point E is her eye level

From the diagram, we observe that the height of skyscraper

/TB/ = /TM/ + /MB/ = x + 1.73m

Now, to determine the height of the skyscraper, we will first determine the value of x

Consider ΔTME

∠TEM = 30°

/TM/ is the opposite and

/ME/ is the adjacent

From the formula

tan \theta =\frac{opposite}{adjacent}

/TM/ = x

/ME/ 389 m

Then, we can write that

tan30^{o} = \frac{x}{389}

∴ x = 389×tan30°

x = 224.58925 m

Recall that the height of the skyscraper /TB/ =  x + 1.73m

∴ /TB/ =  224.58925m + 1.73m

/TB/ = 226.31925m

/TB/ ≅ 226.32m

Hence, the height of the skyscraper is 226.32 meters (rounded to the nearest hundredth of a meter)

Learn more here: brainly.com/question/22062913

6 0
2 years ago
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