Find the probability of drawing 1 snicker first then the probability of drawing another snicker after that, then multiply them together. For the first choice, the probability of drawing a Snickers is 28/33 (snickers/total candy bars). For the second choice, there are only 32 candy bars left, 27 of which are Snickers. So that probability is 27/32, so...
The probability of BOTH things happening is their product 756/1,056 which is 63:88
The independent variable is the one you change to get your dependent variable. in this case, the independent would be the number of quarters you have
Answer:
the probability that Ron will get hit by a pitch exactly once is 36.71%
Step-by-step explanation:
The random variable X= number of times Ron is hits by pitches in 23 plate appearances follows ,a binomial distribution. Where
P(X=x) = n!/(x!*(n-x)!)*p^x*(1-p)^x
where
n= plate appearances =23
p= probability of being hit by pitches = 21/602
x= number of successes=1
then replacing values
P(X=1) = 0.3671 (36.71%)
All you have to do is plug and solve...
2(q+2) + 3q = -26
2q + 4 + 3q = -26
Subtract 4 from the left side and move it to the right...
2q + 4 + 3q = -26
- 4 - 04
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2q + 3q = -30
Now add 3q and 2q together and you get 5q, next divide...
5q = -30
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5 5
Finally, you get q equal to negative 6 (-6)!
