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likoan [24]
3 years ago
15

How many cm of framing are needed to make a picture frame with outside measurements 40 cm and 25 cm​

Mathematics
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

For average sized artwork (about 11x14" to 30x20"), the common mat width is 2". If you artwork is smaller, you might consider a 1.75 or 1.5" mat.

Step-by-step explanation:

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To find the number of bacteria, B, after t hours, use the formula B =1001.32t. How many bacteria were there
masha68 [24]

Answer:

The answer to your question is : B = 5007

Step-by-step explanation:

Formula

               B = 1001.32t

t = 5 hours,

Then

             B = 1001.32 (5)

            B = 5006.6 ≈ 5007

4 0
3 years ago
What is 5+3.2n-6-4.8n=
Svetllana [295]

Answer:

-1-1.6n

Step-by-step explanation:

5+3.2n-6-4.8n

add like terms

-1-1.6n

4 0
3 years ago
Read 2 more answers
From the Equation:<br> (x-8)2 = 16(y+14)
Marat540 [252]

Answer:

x=8y+120

Step-by-step explanation:

7 0
3 years ago
The length of a rectangle is 10m more than twice the width. The
ipn [44]

Answer:

5.6, 21.3

Step-by-step explanation:

Let x be the width.

We know that the length is 10+2x. The area of a rectangle is length times width, so substitute the values.

x*(10+2x)=120

10x+2x^2=120

Divide both sides by 2.

x^2+5x=60

Add 25/4 to both sides so we can make a square.

x^2+5x+ 25/4= 60+25/4=265 /4

Factor the left side.

(x+ 5 /2 )^2= 265 /4

x+2.5=(positive or negative) sqrt(265/4)

x=(positive or negative) sqrt(265/4)-2.5

But, we know that if the equation is negative, the width of the rectangle would be negative. Therefore, x=positive sqrt(265/4)-2.5

Then, we will find the sides.

sqrt66.25-2.5=5.63941, or about 5.6

10+(2(sqrt66.25-2.5))= 21.278821, or about 21.3

3 0
3 years ago
Three fourths minus five fourths with variable m equals one thirteen over 24 what is that simplified
Gre4nikov [31]

Answer: I couldn't solve due to the way you worded it this so I looked it up and got m,24. I don't believe that is the answer..but if you can message me wording it properly I can most definitely solve it for you. :)

3 0
3 years ago
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