How many cm of framing are needed to make a picture frame with outside measurements 40 cm and 25 cm

Mathematics

1 answer:

AnnZ [28]3 years ago

8 0

Answer:

For average sized artwork (about 11x14" to 30x20"), the common mat width is 2". If you artwork is smaller, you might consider a 1.75 or 1.5" mat.

Step-by-step explanation:

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Plz help i will mark brainliest :)))!

Rainbow [258]

Answer:

40 degree

180-57-40= 40

6 0

2 years ago

150 pounds shared into the ratio of 4:1

V125BC [204]

$\begin{cases}x+y=150\smallskip\\\dfrac{x}{y}=\dfrac{4}{1}\end{cases}\Leftrightarrow\begin{cases}x+y=150\smallskip\\x=4y\end{cases}\Leftrightarrow\begin{cases}5y=150\smallskip\\x=4y\end{cases}\Leftrightarrow\begin{cases}y=30\smallskip\\x=120\end{cases}$

$150=120+30$

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3 years ago

Is 85/95 greater than 64/76

madam [21]

85/95 is equal to 0.8947
64/76 is equal to 0.842
Therefore, 85/95 is greater

5 0

3 years ago

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stiv31 [10]

You can use the factors of the volumes 24, 27 and 48:
For example:
8 by 3 by 1 is a total volume of 24
or if you know that 4 times 2 is 8:
4 by 2 by 2
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3 0

3 years ago

Solve using Quadratic Formula <br>x^2 + 3x - 3 = 0

katrin [286]

Answer:

a= 1 , b= 3 , c= –3

$x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 3 \frac{ + }{} {} \sqrt{ {3}^{2} - 4(1)( - 3)} }{2(1)} \\ = \frac{ - 3 \frac{ + }{} \sqrt{9 + 12} }{2} = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = 0.79 \\ x = - 3.79$

I hope I helped you^_^

4 0

3 years ago

How many cm of framing are needed to make a picture frame with outside measurements 40 cm and 25 cm​

How many cm of framing are needed to make a picture frame with outside measurements 40 cm and 25 cm