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WINSTONCH [101]
3 years ago
15

Simplify the equation:

rt[3]{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Bond [772]3 years ago
4 0

To simplify \frac{3}{\sqrt[3]{3} }, we have to follow the rules.

Here are the steps to the question:

Step 1: Follow the radical rule.

\sqrt[n]{a} = a \frac{1}{n}

So, we get \frac{3}{3\frac{1}{3} }.

Next, follow the exponent rule.

\frac{x^{a} }{x^{b} } = x^{a-b}

We get 3^{1} - \frac{1}{3}.

The answer is \frac{3}{\sqrt[3]{3} }.

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Answer:

The perimeter is 28.2 units. I'm not sure about the area.

Step-by-step explanation:

I added up the side lengths that are on the outside of the irregular polygon. I need more time to figure out the area. Hope I was able to help at least a bit.

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Step-by-step explanation:

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Which of these ordered pairs is a solution to the linear inequality 3y – 2x ≥ 8? (1, 3) (3, 1) (–4, 2) (2, –4)
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If the diameter of a wheel is 0.5 meters, then the radius of the wheel is how many centimeters
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The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv
Rina8888 [55]

Answer:

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

\sigma=6.95 represent the population standard deviation

n=36 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

5 0
3 years ago
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