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3 years ago

When completing the square on the equation c 2 11c = 12, the resulting equation is:

1 answer:

6 0

C^2 + 11c = 12

c^2 + 2[11/2] c = 12

[c + 11/2] ^2 - [11/2]^2 = 12

[c +11/2]^2 = 12 +[11/2]^2

[c +11/2]^2 = 12 + 121/4

[c +11/2]^2 =[48+121]/4

[c +11/2]^2 = 169/4 ----> This is the resulting equation

Solving it you get:

c + 11/2 = +/- √(169/4)

c + 11/2 = +/- 13/2

c = 13/2 - 11/2 =2/2 = 1 and

c = -13/2 - 11/2 = - 24/2 = -12

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galina1969 [7]

The arc length of the semicircle is 5π units

<h3>Calculating length of an arc</h3>

From the question, we are to calculate the arc length of the semicircle

Arc length of a semicircle = 1/2 the circumference of the circle

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3 years ago

A boat traveled 120 miles downstream and back. The trip down stream took four hours. The trip back took 12 hours. Find the speed

Alexxandr [17]

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Remember that $rate * time = distance$ . Let's use this formula to write what happens when the boat is going downstream and upstream. When the boat goes downstream, the current goes in the same direction as the boat and speeds it up, so the rate is given by $s + c$ . When the boat is going upstream, the current goes against the boat's movement and slows it down, so the rate is $s - c$ . Thus,

Upstream: $(s + c)(4 h.) = 120 mi.$
Downstream: $(s - c)(12 h.) = 120 mi.$

This is now a system of equations. Let's first divide both sides of each equation by the time to get everything in miles per hour:

$\left \{ {{s + c = 30 mph} \atop {s - c = 10 mph}} \right.$

We can then add the two equations and solve for the speed of the boat in still water first:

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Finally, we can find the speed of the current by plugging the speed of the boat back into one of the previous equations:

$s + c = 30 mph$
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4 years ago