Your answer to the question is B) 7
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Answer:
2352
Step-by-step explanation:
(100 - 2) x 24 = 2400 - 48 = 2352
Answer:
Gradient is 11/4 and y intercept -8
Step-by-step explanation:
11X -4Y =32
transfer 11x on other side
-4y = -11x +32
multiply all termsby -1 so that coefficient of y is positive
4Y = 11X -32
DIVIDE ALL TERMS BY 4
Y = (11/4)X -8
COMPARE THIS WITH Y=mX +C
GRADIENT m is 11/4 and Y intercept C is -8
Gradient is 11/4 and y intercept -8
