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3 years ago

What is the best way to solve integers

Mathematics

2 answers:

Maksim231197 [3]3 years ago

7 0

Answer:

RULE 1: The product of a positive integer and a negative integer is negative. RULE 2: The product of two positive integers is positive. RULE 3: The product of two negative integers is positive. RULE 1: The quotient of a positive integer and a negative integer is negative.

Step-by-step explanation:

nignag [31]3 years ago

4 0

Answer:

An integer is never a fraction, decimal, or percentage, it can only be a whole number. To solve integers and use their properties, learn to use addition and subtraction properties and use multiplication properties. Method 1 Using Addition and Subtraction Properties

Step-by-step explanation:

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What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min

Ilya [14]

Answer:

Value of expression in single logarithm is $\log_3\left(2z^2\right)$ .

Step-by-step explanation:

Given expression is,

$2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)$

Now using logarithmic rule to solve the expression as follows,

Applying product rule of logarithmic,

$\log_c\left(a\right)+\log_c\left(b\right)=\log_c\left(ab\right)$

Therefore,

$2\log_3\left(8z\right)-\log_3\left(3^4-7^2\right)$

Applying power rule of logarithmic,

$a\log_c\left(b\right)=\log_c\left(b^a\right)$

Therefore,

$\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)$

$\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)$

Applying quotient rule of logarithmic,

$\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)$

Therefore,

$\log_3\left(\dfrac{\left(64z^2\right)^2}{3^4-7^2}\right)$

Simplifying,

$\log_3\left(\dfrac{\left(64z^2\right)^2}{81-49}\right)$

$\log_3\left(\dfrac{\left(64z^2\right)^2}{32}\right)$

$\log_3\left(2z^2\right)$

Therefore value of expression is $\log_3\left(2z^2\right)$

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4 years ago

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What is the solution to the system of equations below?

Semenov [28]

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3 years ago

10 to the power of 5/ 10 to the power of 2

MArishka [77]

Answer:

Step-by-step explanation:

((10)^5/10)^2 = 10^1 = 10

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3 years ago

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"the placement test for a college has scores that are normally distributed with a mean of 600 and a standard deviation of 60.if

Tanzania [10]

The cutoff will be evaluated as follows:
let the cutoff be x

but
P(x>0.01)=1-P(x<0.01)=1-0.01=0.99
the z value corresponding to 0.99% is z=2.33
thus
2.33=(x-600)/60
solving for x we get:
139.8=x-600
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4 0

3 years ago

4. Final exam has 20 multiple choices questions. 10 questions have 5 choices and 10 questions have 4 choices. In each question,

Dmitry_Shevchenko [17]

Answer:

1.844

Step-by-step explanation:

Given that final exam has 20 multiple choices questions. 10 questions have 5 choices and 10 questions have 4 choices.

So we divide the questions into two groups I and II.

The no of correct answers in I is called U.

U is binomial with n =10 and p = 0.2

Similarly II group, V the no of correct answers would be binomial

with n =10 and p = 0.25

Our random variable X= U+V

Obviously U and V are independent.

We have var (U) = npq = 1.6

Var (V) = npq = 1.875

Var(X) = Var(U+V)

= Var(U)+Var(V) since U and V are independent

= 3.4

STd dev (X) = $\sqrt{3.4} \\=1.844$

3 0

4 years ago

What is the best way to solve integers ​

What is the best way to solve integers