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2 years ago

What is the best way to solve integers

Mathematics

2 answers:

Maksim231197 [3]2 years ago

7 0

Answer:

RULE 1: The product of a positive integer and a negative integer is negative. RULE 2: The product of two positive integers is positive. RULE 3: The product of two negative integers is positive. RULE 1: The quotient of a positive integer and a negative integer is negative.

Step-by-step explanation:

nignag [31]2 years ago

4 0

Answer:

An integer is never a fraction, decimal, or percentage, it can only be a whole number. To solve integers and use their properties, learn to use addition and subtraction properties and use multiplication properties. Method 1 Using Addition and Subtraction Properties

Step-by-step explanation:

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Can someone plz correct me ?

Verizon [17]

I would guess that the answer would be A) likely but it not it would probably be C) certain

5 0

3 years ago

A line is perpendicular to y = - x - 2 and intersects the point (-5, 10)

Lady_Fox [76]

Answer:

y = x + 15

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = - x - 2. Its slope is -1. A line perpendicular to this will have a slope of 1.

Plug this value (1) into your standard point-slope equation of y = mx + b.

y = 1x + b or y = x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-5, 10). Plug in the x and y values into the x and y of the standard equation.

10 = (-5) + b

Simplify.

10 = -5 + b

Now, add 5 to both sides to isolate b.

15 = b

Plug this into your standard equation.

y = x + 15

This equation is perpendicular to your given equation (y = -x - 2) and contains point (-5, 10)

Hope this helps!

6 0

2 years ago

I need this answered in ONE minute

Helen [10]

Answer:

$x^4 + 4x^3 + 6x^2 + 7x + 2$

Step-by-step explanation:

We are asked to multiply the given polynomials.

$(x^ 2 + 3x + 1) \times (x^2 + x + 2)$

Multiply each term of the first polynomial to each term of the second polynomial.

$x^ 2 \times (x^2 + x + 2) = x^4 + x^3 + 2x^2$

$3x \times (x^2 + x + 2) = 3x^3 + 3x^2 + 6x$

$1 \times (x^2 + x + 2) = x^2 + x + 2$

Add the results

$(x^4 + x^3 + 2x^2) + (3x^3 + 3x^2 + 6x) + ( x^2 + x + 2)$

Combine the like terms

$x^4 + 4x^3 + 6x^2 + 7x + 2$

The answer is written in descending powers of x.

7 0

2 years ago

Please help !!!!! Explain to me and need answer quick

schepotkina [342]

Answer:

We can see that the denominators of both the numbers is not same

So in order to make it same for the both numbers, we will multiply the second number by 2/2 ,(which is basically 1 so it won't affect our calculations)

$\frac{11}{2^2 * 5^2}$ - $\frac{2}{2^2 * 5^2}$