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Alexandra [31]
4 years ago
6

Use the table to identify values of p and q that can be used to factor x2 + x – 12 as (x + p)(x + q).

Mathematics
1 answer:
marta [7]4 years ago
8 0
For this case we have the following polynomial:
 x2 + x - 12
 Factoring we have:
 (x-3) (x + 4)
 We note that the polynomial is written as:
 (x + p) (x + q)
 Thus,
 p = -3
 q = 4
 Answer:
 
The values of p and q that can be used to factor x2 + x - 12 as (x + p) (x + q) are:
 
C. -3 and 4
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How do you do this TwT
tangare [24]

Answer:

Step-by-step explanation:

First step plug the numbers into the equation.

-10/(5+2) = (-10/5) + (-10/2)

Solve both sides of the equation separately.

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-10/5 + -10/2 Multiply the fractions so they can be added together.

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3 years ago
A/b(2x-12)=c/d solve for x
GenaCL600 [577]

Let's solve for x.

Layout equation:

a/b

(2x−12)=c/d

Step 1: Multiply both sides by b.

2ax−12a=bc/d

Step 2: Multiply both sides by d.

2adx−12ad=bc

Step 3: Add 12ad to both sides.

2adx−12ad+12ad=bc+12ad

2adx=12ad+bc

Step 4: Divide both sides by 2ad.

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8 0
4 years ago
Read 2 more answers
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Step-by-step explanation:

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2 years ago
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kolbaska11 [484]

Answer:

look at the sbse below

Step-by-step explanation:

∠DEC ≅ ∠DCE, ∠ACB ≅ ∠GEF,

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i hope this helps you :) it took me a long time

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3 years ago
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