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natita [175]
3 years ago
5

HELP I WILL MAEK BEAINLIST PLEASE

Mathematics
1 answer:
wolverine [178]3 years ago
6 0

Answer:

260,548668 or 260.55 round to the nearest hundreds  

Step-by-step explanation:

Area of the trapezoid:

[(major base + minor base)x height]/2

[(22 + 12) x 12]/2 = 204 cm^2

radius = diameter / 2 = 12 / 2 = 6 cm

Area of a semicircle

(radius^2 x pi)/2 = (6^2 x pi)/2 = 56.548668 cm^2

total area = 204 + 56,548668 = 260,548668 cm^2

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Answer:

The answer is 16

Step-by-step explanation:

8 divided by 2 (2+2)=16

8 0
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Is it possible for two numbers to have a difference of 6, and also a sum of 6?
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Answer:

yes

Step-by-step explanation:

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• `x+y=6`

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Difference:

• `y-x=6`

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Step-by-step explanation:

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How is the Pythagorean theorem related to the distance formula? Explain.
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Answer:

Both formulas can be used to find the distance between two points on the coordinate plane. The vertical leg of the right triangle represents the difference in the y values of the two points. The horizontal leg of the right triangle represents the difference in the x values of the two points. The hypotenuse of the right triangle represents the distance between the two points.

Step-by-step explanation:

i got it right on edge 2021

7 0
3 years ago
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kirza4 [7]

Answer:

\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

Step-by-step explanation:

Let us revise the properties of exponents

  • a^{m}.a^{n}=a^{m+n}
  • \frac{a^{m}}{a^{n}}=a^{m-n}
  • (a^{m})^{n}=a^{m.n}
  • a^{-m}=\frac{1}{a^{m} }

Let us use these properties to solve the question

→ By using the 3rd property above

∵ (a^{2})^{3}=a^{2.3}=a^{6}

∴ \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10} }

→ By using the 1st property above

∵ a^{6}.a^{-3}=a^{6+-3}=a^{6-3}=a^{3}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}

→ By using the 2nd property above

∵ \frac{a^{3}}{a^{10}}=a^{3-10}=a^{-7}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}

→ By using the 4th property above

∵ a^{-7}=\frac{1}{a^{7}}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

8 0
3 years ago
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