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3 years ago

9

is anyone good at math here!??!!??!?!?!?!??!?!?!?!? please don't scroll please answerrrrrrrrrrrrrr this for meeeeeeeeeeeeeeeeeee

ee pleaseeeeeeeeeeeeeeeeeeeeee

1 answer:

riadik2000 [5.3K]3 years ago

3 0

I think its B I’m not 100% sure tho

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A triangle and a rectangle are shown below.

nadezda [96]

Answer:

10 cm

Step-by-step explanation:

From the diagram,

Applying,

lw = 5/2(bh)..................... Equation 1

Where l = length of the rectangle, w = width of the rectangle, b = base of the triangle, h = height of the triangle.

make w the subject of the equation

w = 5(bh)/2l............... Equation 2

From the diagram,

Given: l = 12 cm, b = 6 cm, h = 8 cm

Substitute into equation 2

w = 5(6×8)/(2×12)

w = 10 cm

Hence the width of the rectangle is 10 cm

8 0

2 years ago

Please help quick what is the answer thank you

notka56 [123]

Answer: y= -3x + 4
Explanation: As the general equation of line is y= mx + c where m is the slope of the line and c is the y intercept.
=> for m we need to find the slope of line which is y2 - y1/ x2 - x1
=> 7-1/ -1-1 = 6/-2 = -3
and as we can in the diagram the y intercept is 4
that means our equation for the given line is y = -3x + 4.

5 0

1 year ago

Read 2 more answers

A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w

DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 21.5, \sigma = 4.7$

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

$Z = \frac{X - \mu}{\sigma}$

$1.175 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.175*4.7$

$X = 27.0225$

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

$Z = \frac{X - \mu}{\sigma}$

$1.04 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.04*4.7$

$X = 26.388$

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0

3 years ago

On a certain hot summer's day, 321 people used the public swimming pool. The daily prices are $1.75 for children and $2.00 for a

Paul [167]

Answer:

31 children and 290 adults

Step-by-step explanation:

Let a = number of adults and c = number of children.

a + c = 321

2a + 1.75c = 634.25

Multiply both sides of the the first equation by -2 and add it to the second equation.

-2a - 2c = -642

(+) 2a + 1.75c = 634.25

--------------------------------------

-0.25c = -7.75

Divide both sides by -0.25

c = 31

Use the first equation to find a.

a + c = 321

Substitute 31 for c.

a + 31 = 321

Subtract 31 from both sides.

a = 290

Answer: 31 children and 290 adults

5 0

2 years ago

Read 2 more answers

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

<em><u>Option A</u></em>

<em><u>The solution is:</u></em>

$x = \pm 2i \sqrt{2}$

<em><u>Solution:</u></em>

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$

Thus the solution is found

5 0

2 years ago