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3 years ago

9

is anyone good at math here!??!!??!?!?!?!??!?!?!?!? please don't scroll please answerrrrrrrrrrrrrr this for meeeeeeeeeeeeeeeeeee

ee pleaseeeeeeeeeeeeeeeeeeeeee

1 answer:

riadik2000 [5.3K]3 years ago

3 0

I think its B I’m not 100% sure tho

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<img src="https://tex.z-dn.net/?f=x-%5Csqrt%7Bx%7D%20-2" id="TexFormula1" title="x-\sqrt{x} -2" alt="x-\sqrt{x} -2" align="absmi

Nata [24]

Answer:

(sqrt(x) +1)(sqrt(x)-2)

Step-by-step explanation:

$x - 2 \sqrt{x} + \sqrt{x} - 2 \\ \sqrt{x} ( \sqrt{x} - 2) + 1( \sqrt{x} - 2 ) \\ ( \sqrt{x} + 1)( \sqrt{x} - 2)$

4 0

2 years ago

How can you use ratios and rates to solve problems?

skad [1K]

Rates and ratios help us find relationships between numbers and proportions.

5 0

2 years ago

According to the World Health Organization (WHO) Child Growth Standards, the head circumference for boys at birth is normally di

Elena L [17]

Answer:

$z = \frac{X -\mu}{\sigma}$

This z score tell to us how many deviations we are below or above the mean for a given normal distribution.

For the case of Eddie we got:

$z= \frac{33.2-34.5}{1.3}= -1$

And for the case of Sue we got:

$z = \frac{32.7-33.9}{1.2}= -1$

So then for both cases we see that Eddie and Sue are 1 deviation below the true mean for each gender so then the best conclusion for this case would be:

C.They are the same size relative to other children of the same sex.

Step-by-step explanation:

We can define the random variable X as the head circumference for boys at birth and we know that the distribution for X is given by:

$X\sim N(\mu = 34.5, \sigma=1.3)$

Similarly we can define the random variable Y as the head circumference for boys at birth and we know that the distribution for Y is given by:

$Y\sim N(\mu = 33.9, \sigma=1.2)$

And we know that Eddie was born with 33.2 cm and Sue with 32.7 cm for the head circumference . Since we are interested to determine which child's head circumference is smaller relative to other children of the same sex, we can use the z score formula given by this formula:

$z = \frac{X -\mu}{\sigma}$

This z score tell to us how many deviations we are below or above the mean for a given normal distribution.

For the case of Eddie we got:

$z= \frac{33.2-34.5}{1.3}= -1$

And for the case of Sue we got:

$z = \frac{32.7-33.9}{1.2}= -1$

So then for both cases we see that Eddie and Sue are 1 deviation below the true mean for each gender so then the best conclusion for this case would be:

C.They are the same size relative to other children of the same sex.

5 0

2 years ago

Which term best describes the shape of this distribution?

borishaifa [10]

The shape of the distribution described the Left skewed.

<h3>What is left- skewed histogram?</h3>

A left skewed histogram is a histogram that attains a peak (which is the mode) towards the right side of the graph and has a “tail” towards the left side.

A histogram in which most of the data falls to the left of the graph's peak is known as a left-skewed histogram.

A left-skewed histogram is a type of histogram that is not symmetrical and in which the peak of the graph lies to the right of the middle value or the median.

Hence, considering the above definition the given histogram data falls on right side.

So, it is left skewed graph.

Learn more about left- skewed graph here:

brainly.com/question/1518646

#SPJ1

4 0

2 years ago

Find the greatest common factor of the following 45m 6m5

lisabon 2012 [21]

45m 6m^5 usually helps to list the factors of each number first,
1x45=453x15=455x9=45
1x6=62x3=6
so the biggest number that fits into both would be 3, and the biggest amount you can take of any variable would be the amount of that lowest variable. when given an "m" and "m^5", you can only take out one "m", because when m÷m=1, that means you can't take any more "m's" out. if it were m^2 and m^5 you would take out m^2 :)
so your final answer would be"3m" and if you were taking it out of an equation (if you had 45m+/-6m^6)would look like 3m(15+/-2m^4

8 0

3 years ago