2-29 it was b but if you lo
Answer:
Your answer is B
Step-by-step explanation:
Take 300 and subtract it by 99 you'll get 201
3 times 67 is 201
Which is why your answer is B!
Hope this helps! -Queenb369
(P.S, If you could give me the brainlist if i'm right, that will be great thanks!)
<span>there are 16 cups in one gallon</span>
Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x
Table 1:
y = k × x
30 = k × 5
30 = 5k
k = 30/5
k = 6
So,
<em>y = 30 </em>
<em>y = 30 k = 6</em>
<em>y = 30 k = 6x = 5</em>
<em>y = 30 k = 6x = 5Equation: y = 6x</em>
y = k × x
y = 10 × 8
y = 80
So,
<em>y = 80 </em>
<em>y = 80 k = 10</em>
<em>y = 80 k = 10x = 8</em>
<em>y = 80 k = 10x = 8Equation: y = 10x</em>
y = 3x
18 = 3x
x = 18/3
x = 6
So,
<em>y = 18</em>
<em>y = 18k = 3</em>
<em>y = 18k = 3x = 6</em>
<em>y = 18k = 3x = 6Equation: y = 3x</em>
y = 2x²
72 = 2x²
x² = 72/2
x² = 36
x = √36
x = 6
So,
<em>y = 72</em>
<em>y = 72k = 2</em>
<em>y = 72k = 2x = 6</em>
<em>y = 72k = 2x = 6Equation: y = 2x²</em>
Table 2:
y = k/x
5 = k/6
5 × 6 = k
30 = k
So,
<em>y = 5</em>
<em>y = 5k = 30</em>
<em>y = 5k = 30x = 6</em>
<em>y = 5k = 30x = 6Equation: y = 30/x</em>
y = k/x
y = 36/4
y = 9
So,
<em>y = 9</em>
<em>y = 9k = 36</em>
<em>y = 9k = 36x = 4</em>
<em>y = 9k = 36x = 4Equation: y = 36/x</em>
y = 60/x
20 = 60/x
20x = 60
x = 60/20
x = 3
So,
<em>y = 20</em>
<em>y = 20k = 60</em>
<em>y = 20k = 60x = 3</em>
<em>y = 20k = 60x = 3Equation: y = 60/x</em>
y = 24/x
y = 24/12
y = 2
So,
<em>y = 2</em>
<em>y = 2k = 24</em>
<em>y = 2k = 24x = 12</em>
<em>y = 2k = 24x = 12Equation: y = 24/x</em>
Read more:
brainly.com/question/472621
Use the power rule for differentiation:
You can use this formula if you remember that a root is just a rational exponential:
![\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%5Cln%28x%29%20%3D%20%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20)
So, remembering that the derivative of the logarithm is 1/x, you have
Which you can rewrite as
![\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7D%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B1%7D%7B4%7D-1%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%5Cdfrac%7B1%7D%7B4%7D%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B-3%7D%7B4%7D%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%5Cdfrac%7B1%7D%7B4%7D%5Cdfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B%5Cln%28x%29%29%5E3%7D%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%20%5Cdfrac%7B1%7D%7B4x%5Csqrt%5B4%5D%7B%5Cln%28x%29%29%5E3%7D%7D%20)
