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oksano4ka [1.4K]
3 years ago
15

All the members of a construction crew work at the same pace. Six of them working together are able to pour foundation in 22 hou

rs.
a)How many hours would this job take if the number of workers decreased by factor of 2?
c)How many hours would this job take if the number of workers increased by factor of 4?
Mathematics
2 answers:
laiz [17]3 years ago
8 0

Answer:

(a). 11

(b). 16

Step-by-step explanation:

(a). 6=22

3=x solve for x doing 22(3)/6

(b). 6=22

24=x solve for x doing 22(24)/6

Ghella [55]3 years ago
3 0

Answer:a) 44hrs

b)5.5hrs

Step-by-step explanation

6 workers take 22hrs

a) if the workers decreased by factor of 2, number of workers =3. The time increases by factor of 2

Therefore, 3 workers take

22*2 = 44hrs

b) if the workers increased by factor of 4,

Number of workers = 6*4= 24

The time decreases by factor of 4

Therefore, 24 workers take

22/4= 5.5 hrs

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Answer:

5 x 2 -3 = 7

Step-by-step explanation:

i mean.... thats all

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3 years ago
Suppose that a box contains 6 cameras and that 3 of them are defective. A sample of 2 cameras is selected at random. Define the
mezya [45]

Answer: 1/5, 1/2, 0.

Step-by-step explanation:

given data:

no of cameras = 6

no of cameras defective = 3

no of cameras selected = 2

Let p(t):=P(X=t)

p(2)=m/n,

m=binomial(3,2)=3!/2!= 3

n=binomial(6,2)=6!/2!/4! = 15

p(3)= 3/15

= 1/5.

p(1)=m/n,

m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5

n=binomial(6,2)= 15

p(2)= 7.5/15

= 1/2

p(0)=m/n,

m=0

p(0)=0

7 0
3 years ago
Read 2 more answers
Evaluate the function f(x) = x2 + 3x for both of the following:
marissa [1.9K]
F(x)=x²+3x

f(0)=0²+3*0=0+0=0

Answer: f(0)=0

f(4)=4²+3*4=16+12=28

Answer: f(4)=28
6 0
3 years ago
(5x²+2) - (-4x²+7)+(-3x²-5)
svp [43]

Answer:

6x^2   -10

Step-by-step explanation:

(5x²+2) - (-4x²+7)+(-3x²-5)

Distribute the minus sign

(5x²+2) +4x²-7 +(-3x²-5)

Combine like terms

5x²+4x²-3x²  +2-7-5

6x^2              -10

6 0
3 years ago
10. The sum of the digits of a three-digit number is 11. If the digits are reversed, the new number is 46
Zarrin [17]

Answer:

hope this helps

Step-by-step explanation:

The sum of the digits of a three-digit number is 11.

If the digits are reversed, the new number is 46 more than five times the old number.

If the hundreds digit plus twice the tens digit is equal to the units digit, then what is the number?

:

Write an equation for each statement:

:

"The sum of the digits of a three-digit number is 11."

x + y + z = 11

:

The three digit number = 100x + 10y + z

The reversed number = 100z + 10y + x

:

" If the digits are reversed, the new number is 46 more than five times the old number."

100z + 10y + x = 5(100x + 10y + z) + 46

100z + 10y + x = 500x + 50y + 5z + 46

combine on the right

0 = 500x - x + 50y - 10y + 5z - 100z + 46

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:

"the hundreds digit plus twice the tens digit is equal to the units digit,"

x + 2y = z

x + 2y - z = 0

:

Three equations, 3 unknowns

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x + y + z = 11

x +2y - z = 0

-----------------Addition eliminates z

2x + 3y = 11

From the 2nd equation statement, we know that the 1st original digit has to be 1

2(1) + 3y = 11

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3y = 9

y = 3 is the 2nd digit

then

1 + 3 + z = 11

z = 11 - 4

z = 7

:

137 is the original number

:

:

Check solution in the 2nd statement

If the digits are reversed, the new number is 46 more than five times the old number."

731 = 5(137) + 46

731 = 685 + 46

7 0
3 years ago
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