Answer:
To find the surface area of a cube, use the formula: surface area = 6s^2, where s is the length of one of the sides. If you don't know the length of the sides, you can find the surface area using volume. Just find the cube root of the volume, which is equal to the length of one side of the cube.
Step-by-step explanation:
so in this case:
SA= 6(3)^2
= 18^2
= 324
What are the different statements
Answer:
And if we solve for a we got
And for this case the answer would be 35185 the lowest 1% for the salary
Step-by-step explanation:
Let X the random variable that represent the salary, and for this case we can assume that the distribution for X is given by:
Where
and
And we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.01 of the area on the left and 0.99 of the area on the right it's z=-2.33. On this case P(Z<-2.33)=0.01 and P(z>-2.33)=0.99
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
And for this case the answer would be 35185 the lowest 1% for the salary
<span>Look
for the sum of 56 and 64, written as the product of its GCF and another sum.
First, let’s find the greatest common factor of both given numbers:
=> 56 = 1, 2, 4, 7, 8, 13, 28 and 56
=> 64 = 1, 2, 4, 8, 16, 32, and 64
Now, we need to find the greatest common factor between the two numbers. The GCF
of the 2 numbers is 8.
=> 56 / 8 = 7
=> 64 / 8 = 8
=> 56 + 64 = 120
=> (8 x 7) + (8 x 8)
=> 56 + 64
=> 120.</span><span>
</span>
Given :
Miki has 104 nickels and 88 dimes.
She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.
To Find :
Largest number of groups she can have .
Solution :
In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .
Now , factorizing both of them , we get :

Form above , we can say that common factors are :

Therefore , the largest number of groups she can have is 8 .
Hence , this is the required solution .