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3 years ago

What is 8.05 × 10-5 in standard notation?

Mathematics

1 answer:

Makovka662 [10]3 years ago

8 0

Answer:0.0000805

Step-by-step explanation:

Edgenuity says it’s right

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Drag and drop an answer to each box to correctly complete the proof.

Annette [7]

It is given that m ∥ n, m∠1 = 50° , and m∠2 = 42°. By the triangle sum theorem, m∠3 = 88°. Because corresponding angles formed by two parallel lines and a transversal are congruent, ∠3 ≅ ∠4. By the angle congruence theorem, m∠3 =m∠4. Using substitution, 88°=m. Angles 4 and 5 form a linear pair, so by the linear pair postulate, m∠4 + m∠5=180°. Substituting gives 88° + m∠5=180°. Finally, by the subtraction property of equality, m∠5 = 92°.

5 0

3 years ago

Read 2 more answers

Express the ratio 16:9 as a ratio to 1.

never [62]

Answer:

(16/9):1

Step-by-step explanation:

8 0

3 years ago

Which equation is not true 12/10=6/5 3/1=30/10 6/2=2/3 8/6=16/12

blsea [12.9K]

Answer:

third one is not true means wrong

6 0

3 years ago

En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz

nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

= 180° - 72° - 64°

= 44°

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

= 180° - 90° - 72°

= 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

= 180° - 18° - 36°

= 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

= 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

= 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

= 180° - 14° - 54°

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

d = angle BQP - angle PBQ

= 112° - 14°

= 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0

3 years ago

Find the measure of the missing angle

Leokris [45]

Answer:

z = 69°

Step-by-step explanation:

The sum of all interior angles in a quadrilateral is 360°, and a right angle is worth 90°. We're given the values of the interior angles as 90, 122, 79, and z degrees.