3 years ago

Help please! - - - -

Mathematics

2 answers:

Alina [70]3 years ago

7 0

Me mean changes to 58 and the median turns to 56

Elina [12.6K]3 years ago

4 0

The mean would change from 53.75 to 58.

The median would change from 54 to 56.

You might be interested in

PLEASE HELP WILL GIVE 100 POINTS!! WILL ALSO MARK BRAINLIEST FASTT!!!The two dot plots below show the heights of some sixth grad

Oksana_A [137]

Answer:

1.4

Step-by-step explanation:

add the MADs together then divide them by two.

3 0

3 years ago

Read 2 more answers

Help me on 12 and 13 please and fast

lys-0071 [83]

Answer:

12. B , 13. 4

Step-by-step explanation:

$12. \frac{3}{12}+\frac{1}{12} +\frac{2}{12} =\frac{6}{12} =\frac{1}{2} \\13. 5-(\frac{2}{10} *5)=4$

3 0

4 years ago

Can anyone help me with number 6 & 8?

Liono4ka [1.6K]

$\bf \begin{cases} f(x)=x-3\\ g(x)=x^2+1\\ h(x)=-4x+1\\ -------&--------\\ (h\circ g\circ f)(x)=&(h\circ g(~f(x)~)\\ &h(~~g(~~f(x)~~)~~) \end{cases} \\\\\\ g(~~f(x)~~)=[f(x)]^2+1\implies g(~~f(x)~~)=[x-3]^2+1 \\\\\\ g(~~f(x)~~)=[x^2-6x+9]+1\implies \boxed{g(~~f(x)~~)=x^2-6x+10} \\\\\\ h(~~g(~~f(x)~~)~~)=-4[g(~f(x)~)]+1 \\\\\\ h(~~g(~~f(x)~~)~~)=-4[x^2-6x+10]+1 \\\\\\ h(~~g(~~f(x)~~)~~)=-4x^2+24x-40+1 \\\\\\ h(~~g(~~f(x)~~)~~)=-4x^2+24x-39$