A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
Answer:
I think it is 3 + (6 + 2) or 11
Step-by-step explanation:
You first find 3 pens and 6 markers. Then you find 2 more markers at the bottom of your locker. The common answer I think would be 3 + (6 + 2) or If your teacher wants a whole answer, 11.
I hope this helped
I am sorry if I got it incorrect
Answer:
x>-5 x ≤10
Step-by-step explanation:
-35/7=-5
7x/7=x
3x/3=x
30/3=10
Miguel: 500 out of 750 students have part time jobs.
500 ÷ 250 = 2
750 ÷ 250 = 3
500:750 = 2:3
A) 200 out of 300 ⇒ 200/100 and 300/100 ⇒ 2:3
B) 700 out of 1100 ⇒ 700/100 and 1100/100 ⇒ 7:11
C) 800 out of 1200 ⇒ 800/400 and 1200/400 ⇒ 2:3
D) 9000 out of 1300 ⇒ 9000/100 and 1300/100 ⇒ 90:13
Among the choices, Choice B could represent Kureshi's Data because it is not proportional to the data of Miguel.
Choice D is not possible. You cannot have a result that is way beyond the scope of your population. It is impossible to get 9000 students out of only 1300 students.
