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Sergeeva-Olga [200]
3 years ago
11

PLZ HELP ITS DUE NOW NO LINKS

Mathematics
1 answer:
Leni [432]3 years ago
6 0

Answer:

show the options

Step-by-step explanation:

Brainliest?

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The total you must pay back on the loan is
Aleksandr [31]
795 x 6.52= 51.834
51.834 x 3= 155.502

Final answer 155.50
4 0
3 years ago
A snail moves at the speed of 76 millimeters per minute. Nancy writes the following steps to calculate this speed in centimeters
gizmo_the_mogwai [7]

Answer:

The step 3 is incorrect in the conversion, is not necessary

Step-by-step explanation:

we have

The speed is 76\frac{mm}{min}

we know that

1 mm=0.1 cm

1 min=1/60 h

so

76\frac{mm}{min}=76(0.1)/(1/60)=76(0.1)(60)=456\frac{cm}{h}

step 1

Multiply 76 by 0.1

76(0.1)=7.6

The step 1 is correct

step 2

Multiply the result obtained in step 1 by 60.

7.6(60)=456

The step 2 is correct

step 3

Multiply the result obtained in step 2 by 60

<u><em>This step is not correct</em></u>

therefore

The step 3 is incorrect in the conversion, is not necessary

4 0
3 years ago
Simplify: -m(7m + 3) – 4m2<br>A. 12m+4<br>B. -11m2-3m<br>C. -11m2+6m<br>D.5 m + 4 ​
Mars2501 [29]

Answer:

- m(7m + 3) - 4 {m}^{2}  \\  - 7m^{2}  - 3m - 4 {m}^{2} \\   - 11 {m}^{2}  - 3m

6 0
4 years ago
-50 1/2 +[-12.3] simplify expression
ololo11 [35]

Answer:

-62.8

Step-by-step explanation:

  • -50 \frac{1}{2} - 12.3
  • -50.5 - 12.3
  • -62.8
6 0
3 years ago
Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim
Xelga [282]

Answer: P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = \frac{2.\pi}{B}

C is the phase shift or horizontal shift: \frac{C}{B}

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = \frac{largest - smallest}{2}

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = \frac{6.9-4.4}{2}

a = 1.25

<u>b</u>

A time period for Pluto is T=66 years:

66 = \frac{2.\pi}{b}

b = \frac{\pi}{33}

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = \frac{largest+smallest}{2}

d = \frac{6.9+4.4}{2}

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

8 0
3 years ago
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