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butalik [34]
3 years ago
15

Condense the logarithm2 log c + 3 log k​

Mathematics
1 answer:
Viktor [21]3 years ago
4 0

Given:

The expression is

2\log c+3\log k

To find:

The value after condense the logarithm.

Solution:

We have,

2\log c+3\log k

Using properties of logarithm, we get

=\log c^2+\log k^3            [\because \log x^n=n\log x]

=\log (c^2k^3)            [\because \log (ab)=\log a+\log b]

Therefore, the required value is \log (c^2k^3).

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(3x^2)(4x)=12x^3 is 3x^2 a factor of 12x^3
Diano4ka-milaya [45]

Answer:

(3x2 + 1) • (4x - 1)

Step-by-step explanation:

Equation at the end of step  1  :

(((12 • (x3)) -  3x2) +  4x) -  1

Equation at the end of step  2  :

(((22•3x3) -  3x2) +  4x) -  1

Checking for a perfect cube :

12x3-3x2+4x-1  is not a perfect cube

Trying to factor by pulling out :

Factoring:  12x3-3x2+4x-1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  4x-1

Group 2:  12x3-3x2

Pull out from each group separately :

Group 1:   (4x-1) • (1)

Group 2:   (4x-1) • (3x2)

              -------------------

Add up the two groups :

              (4x-1)  •  (3x2+1)

Final result :

(3x2 + 1) • (4x - 1)

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Answer:

Step-by-step explanation:

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