Answer:
2 1/6 chapters per hour
Step-by-step explanation:
Find the unit rate, as follows:
9.75 chapters
----------------------- = 2.166666 ... chapters per hour, or
4.5 hours 2 1/6 chapters per hour
Answer:
a. 0.4
b. 0.6
c. 0.6493
Step-by-step explanation:
p(checking work email) = p(A) = 0.40
p(staying connected with cell phone) = p(B) = 0.30
p(having laptop) = p(c) = 0.35
p(checking work mail and staying connected with cell phone) = p(AnB) = 0.16
p(neither A,B or C) = p(AuBuC)
= 1-42.8%
= 0.572
p(A|C) = 88% = 0.88
p(C|B) = 70% = 0.7
a. What is the probability that a randomly selected traveler who checks work email also uses a cell phone to stay connected?
p(B|A) = p(AnB)/p(A)
= 0.16/0.4
= 0.4
b. What is the probability that someone who brings a laptop on vacation also uses a cell phone to stay connected?
p(B|C) = P(C|B)p(B)/p(C)
= 0.7x0.3/0.35
= 0.6
c. If the randomly selected traveler checked work email and brought a laptop, what is the probability that he/she uses a cell phone to stay connected?
p(A|BnC)
= P(BnAnC)/p(AnC)
= p(AnC) = p(A|C).p(C)
= 0.88x0.35
= 0.308
p(AnBnC) = p(AuBuC)-p(a)-p(b)+ p(AnB)+p(AnC)+p(BnC)
p(BnC) = 0.7x0.3
= 0.21
p(AnBnC) = 0.572-0.4-0.3-0.35+0.16+0.308+0.21
= 0.2
p(A|BnC) = 0.2/0.308
= 0.6493
Answer:
f(x) = - 2x - 1
Step-by-step explanation:
Let the linear function f(x) is given by f(x) = ax + b where a and b are unknown constants.
Given that f(0) = -1 and f(2) = -5
Hence, a(0) + b = - 1, ⇒ b = - 1
Again from the condition given
a(2) + b = -5, ⇒ 2a - 1 = - 5, ⇒ 2a = - 4, ⇒ a = - 2.
Therefore, the linear function is f(x) = - 2x - 1 (Answer)
Answer:
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Step-by-step explanation:
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