Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
Step-by-step explanation:
5(x + 3) Remove the brackets.
5*x + 3*5 Combine
5x + 15
Answer:
From least to greatest
23* 1/4, 23* 2/2, 23* 13/5
Explanation
In order to do this without multiplication, place the fractions in ascending order.
The denominators of these fractions have 20 as a common multiple.
2/2 • 10 = 20/20
1/4 • 5 = 5/20
13/5 • 4 = 52/20
From this it logically follows that the fractions in ascending order are:
1/4, 2/2, 13/5
Therefore the products in ascending order are:
23* 1/4, 23* 2/2, 23* 13/5
Answer:
4.718592
Step-by-step explanation:
To get to -14.4 from 18 you multiply 18 x 0.8
Repeat that until you get to the 7th term
18 (1st)
18 x 0.8 = -14.4 (2nd)
-14.4 x 0.8 = 11.52 (3rd)
11.52 x 0.8 = 9.216 (4th)
9.216 x 0.8 = 7.3728 (5th)
7.3728 x 0.8 = 5.89824 (6th)
5.89824 x 0.8 = 4.718592 (7th)
