The perpendicular line would have a slope of 1/3.
Perpendicular lines have opposite and reciprocal slopes. So first we have to find the slope of the original line. We can do this by solving the equation for y.
5x - 9y = 1
-9y = -5x + 1
y = 5/9x - 1/9
To do the opposite, take the original slope (5/9) and change the sign (-5/9).
To do the reciprocal, take the slope we changed (-5/9) and flip it as a fraction (-9/5).
This gives us a new slope of
I hope this helps you
x.3x+x.(-1)+5.3x+5.(-1)-(x^2-2.4.x+16)
3x^2-x+15x-5-x^2+8x-16
2x^2+22x-21
Answer:
it's opinion A
Step-by-step explanation:
I took the quiz
Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
Collect results:Answer: {x = 4 {y = 1
Please note the { are supposed to span over both equations but it interfaces doesn't allow it. Please see attachment for clarification.
Answer:
Step-by-step explanation: