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2 years ago

11

What size rectangular floor can be completely covered by using only 3 x 3 ft tiles OR 5 x 5 ft tiles? Remember, you cant cut ti

les or combine the two sizes.

1 answer:

AVprozaik [17]2 years ago

5 0

Answer would be 5 x 5

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A triangle who has two sides to the links of 7 AM and 12 PM which of the following wants to represent the length of the third si

IgorLugansk [536]

Answer:

What do you mean by writing time?

Step-by-step explanation:

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2 years ago

Read 2 more answers

1) 5x-2y=4. 2) 3x-5y=13 x-2y=5<br>3x+y=9

Natali [406]

$\left\{\begin{array}{ccc}5x-2y=4\\3x+y=9&/\cdot2\end{array}\right\\+\left\{\begin{array}{ccc}5x-2y=4\\6x+2y=18\end{array}\right\\----------\\.\ \ \ \ \ 11x=22\ \ \ \ /:11\\.\ \ \ \ \ \ \ x=2\\\\3\cdot2+y=9\\6+y=9\\y=9-6\\y=3\\\\Answer:x=2;\ y=3$

$\left\{\begin{array}{ccc}3x-5y=13\\x-2y=5\end{array}\right\\\left\{\begin{array}{ccc}3x-5y=13\\x=2y+5\end{array}\right\\\\substitute:\\\\3(2y+5)-5y=13\\6y+15-5y=13\\y=13-15\\y=-2\\\\x=2\cdot(-2)+5=-4+5=1\\\\Answer:x=1;\ y=-2.$

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2 years ago

Can anyone help me with my math i'm really behind on it.

statuscvo [17]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

1. Find the Least Common Multiple of these two monomials:<br> See picture

gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em /> $LCM=120a^4b^7c^5$ <em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

$12a^4b^2c^5$

$40a^3b^7c^1$

The prime factors of the first monomial are:

$2^2,3,a^4,b^2,c^5$

The prime factors of the second monomial are:

$2^3,5,a^3b^7c^1$

LCM = Multiply $2^3*3*5*a^4*b^7*c^5$

These are all the factors the greatest number of times they occur.

Operating:

$LCM=8*15*a^4*b^7*c^5$

$\boxed{LCM=120a^4b^7c^5}$

The last choice is correct

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3 years ago

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2 years ago