<span>-3 = x^2 + 4x + 1
Add 3 to both sides.
0 = x^2 + 4x + 4
Switch sides.
x^2 + 4x + 4 = 0
For the quadratic formula, a = 1, b = 4, c = 4
discriminant = b^2 - 4ac = 4^2 - 4(1)(4) = 16 - 16 = 0
When the discriminant equals zero, there is a single real solution.
Answer: There is a single, real solution.</span>
Take a look at this file for help!
Answer:
The area of the picture is
Step-by-step explanation:
Let
x-----> the length side of the square picture
we know that
The area of the picture plus the frame minus the area of the picture is equal to the area of the frame alone
The area of the picture is
Answer:
The answer is A (-3,4,6).
Step-by-step explanation:
1 Solve for z in -3x-4y+z=-1
z=3x-1+4y
2 Substitute z=3x-1+4y into 2x+y-z=-8
-x-3y+1=-8
3 Substitute z=3x-1+4y into x+8y-z=23
-2x+4y+1=23
4 Solve for x in -x-3y+1=-8
x=-3y+9
5 Substitute x=-3y+9 into z=3x-1+4y
z=-5y+26
6 Substitute x=-3y+9 into -2x+4y+1=23
10y-17=23
7 Solve for y in 10y-17=23
y=4
8 Substitute y=4 into z=-5y+26
z=6
9 Substitute y=4 into x=-3y+9
x=-3
10 Therefore,
x=-3
y=4
z=6
Ull count the decimal places after the number