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2 years ago

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7. Kayce made $16 to $28 dollars per horse for grooming them. What is a reasonable amount of money she made if she groomed 18 ho

rses this month?
F. $280 G. $548 H. $380 J. $200
I need help lol on the easiest things

1 answer:

juin [17]2 years ago

5 0

The answer should be h.380

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The sum of 7/8 and 4/9 is closer to 0,1,2,or 3?

tresset_1 [31]

2 because you make them with the same denominators that both go into each other EX: 8x9=72 7/8 now equals 63/72 and 4/9 now equals 28/72 now add them together 63/72 + 28/72= 91/72= 1 19/72

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2 years ago

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

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2 years ago

3 intersecting lines are shown. A line contains points E, D, A, and B. Another line intersects the line at point A and contains

GREYUIT [131]

Answer:

The one with arrows are the answers

->Line segment E B is bisected by Line segment D F .

->A is the midpoint of Line segment F C .

Line segment F C bisects Line segment D B.

->Line segment E B is a segment bisector.

->FA = One-halfFC.

Line segment D A is congruent to Line segment A B .

Step-by-step explanation:

I did it on edge and got it right

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2 years ago

Read 2 more answers

the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 48 M. the length of the alley

Firdavs [7]

Answer:

Length is 20 m and width is 4 m.

Step-by-step explanation:

Given:

Perimeter of the rectangular alley, $P=48\textrm{ m}$

Length is 5 times the width.

Let width be $x$ .

So, as per question,

Length, $l = 5x$

Now, perimeter of rectangle is given as:

$P=2(l+b)$

Plug in 48 for $P$ , $5x$ for $l$ and $x$ for b.

$48=2(5x+x)\\48=2(6x)\\48=12x\\x=\frac{48}{12}=4$

Therefore, width is 4 m.

Length is $5x=5\times 4=20$ m.

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3 years ago

Solve the equation for y. Identify the slope and y-intercept then graph the equation.

viva [34]

Answer:

y = -3 m = -1 b = 3

Step-by-step explanation:

-3y=3x-9

To isolate the y variable, divide both sides by -3.

y = -1x + 3

y = -3

m = -1

b = 3

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2 years ago