1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dybincka [34]
3 years ago
13

Find the area of ​​the painted part of the image below. (Units in m)

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

16

Step-by-step explanation:

4×4=16

\frac{1}{2}  \times 8 \times 4 = 16

You might be interested in
PLEASE HELP THIS ONE AND BEFORE THIS ONE.<br><br>AND DO YOU KNOW WHICH BOOK THIS PAGE US FROM.​
balandron [24]

Answer:

Richmond, October 22, 1780.

Sir,

I have this morning received certain information of the arrival of a hostile fleet in our bay, of about sixty sail. The debarkation of some light-horse, in the neighborhood of Portsmouth, seems to indicate that as the first scene of action.We are endeavoring to collect as large a body to oppose them as we can arm: this will be lamentably inadequate, if the enemy be in any force. It is mortifying to suppose that a people, able and zealous to contend with their enemy, should be reduced to fold their arms for want of the means of defence. Yet no resources, that we know of, ensure us against this event. It has become necessary to divert to this new object, a considerable part of the aids we had destined for General Gates.We are still, however, sensible of the necessity of supporting him, and have left that part of our country nearest him uncalled on, at present, that they may reinforce him as soon as arms can be received. We have called to the command of our forces, Generals Weeden and Muhlenburg, of the line, and Nelson and Stevens of the militia. You will be pleased to make to these such additions as you may think proper.As to the aids of men, I ask for none, knowing that if the late detachment of the enemy shall have left it safe for you to spare aids of that kind, you will not await my application. Of the troops we shall raise, there is not a single man who ever saw the face of an enemy. Whether the Convention troops will be removed or not, is yet undetermined. This must depend on the force of the enemy, and the aspect of their movements.

I have the honor to be

your Excellency's most obedient,

Step-by-step explanation:

im am so sorry i honestly don't know this one

5 0
3 years ago
NEED ANSWER QUICK - NO FALSE ANSWERS BRAINLIEST WILL BE GIVEN
fenix001 [56]

Answer:

f(-2) =2

Step-by-step explanation:

f(-2) means find the y value when x=-2

The y value is 2 when x=-2

6 0
3 years ago
Read 2 more answers
F(x)=6(-x+3), what is the value of f(-1)
IgorLugansk [536]

Replace x in the equation with -1 and solve:

6(-(-1) + 3)

Simplify the parentheses: 6(1 + 3)

Add inside the parentheses:

6(4)

Multiply

6 x 4 = 24

Answer : 24

3 0
2 years ago
drug sniffing dogs must be 95% accurate in their responses because their handlers don't want them to miss durgs and also don't w
GenaCL600 [577]

Answer:

95% Confidence interval:  (0.8449,0.9951)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

Number of times the dog is right, x = 46

\hat{p} = \dfrac{x}{n} = \dfrac{46}{50} = 0.92

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.92 \pm 1.96(\sqrt{\dfrac{0.92(1-0.92)}{50}})\\\\ = 0.92\pm 0.0751\\\\=(0.8449,0.9951)

(0.8449,0.9951) is the required 95% confidence interval for the proportion of times the dog will be correct.

7 0
3 years ago
Someone please help me on this. Please help me. Please don’t put a link.
Elenna [48]

Given:

The figure of a triangle LMN.

P is the centroid of triangle LMN.

To find:

14. Find the value of PN if QN=30.

15. Find the value of PN if QN=9.

Solution:

We know that the centroid in the intersection of medians of a triangle and centroid divides each median in 2:1.

Since P is the centroid it means NQ is the median from vertex N. It means P divides the median NQ in 2:1. So, PN:PQ=2:1.

14. We have QN=30.

PN=\dfrac{2}{2+1}QN

PN=\dfrac{2}{3}(30)

PN=2(10)

PN=20

Therefore, the value of PN is 20 when QN=30.

15. We have QN=9.

PN=\dfrac{2}{2+1}QN

PN=\dfrac{2}{3}(9)

PN=2(3)

PN=6

Therefore, the value of PN is 6 when QN=9.

4 0
3 years ago
Other questions:
  • Determine whether the function has a maximum or minimum value. <br> f(×)= x^2+9
    11·2 answers
  • Find the value of v in the equation below(in picture)
    11·1 answer
  • The circumference of a coin is 8π What is the radius? What is the diameter?
    13·2 answers
  • Simplify the expression 2^5*3^4/2^7*3^2
    7·1 answer
  • Lucy is a dress maker. She sews \dfrac47
    12·1 answer
  • Evaluate - x - y - z when x = - 8, y = 6 and z = -4.
    15·1 answer
  • (14x2 – 11x – 2) + (3x2 + 6x – 5) simplify
    10·2 answers
  • 3.2 worksheet angles
    5·1 answer
  • Which set of transformations would prove triangle GFE ~ triangle GHI?
    12·2 answers
  • 1.4×10−5 and 2.8×10−4
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!