$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\underline{1}\implies \cfrac{\underline{1}}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{\underline{1}}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{\underline{1}}\implies -1}}$

so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})~\hspace{10em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y-5=-x+2\implies y=-x+7$

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2 years ago

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The range, a measure of variability, Group of answer choices is the difference between the largest (L) and smallest (S) value in

Vlad [161]

<u>The correct answer is </u><u>all of the above.</u>

Why is the range the most convenient measure of variability?

Your data's spread from the lowest to the greatest value in the distribution is indicated by the range.
The calculation of this variability index is the simplest.
Simply subtract the lowest value from the highest value in the data set to determine the range.

How do you find the range?

The difference between the lowest and highest values in a list or set is known as the range.
Put all the numbers in order before determining the range. The lowest number should then be subtracted from the highest.
The range of the list is provided in the response.

Learn more about range

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1 year ago