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2 years ago

A side of the triangle below has been extended to form an exterior angle of 62°. Find the value of xx.

Mathematics

1 answer:

umka21 [38]2 years ago

3 0

Answer:

Photo?

Step-by-step explanation:

If there is a photo linked I dont see it

Also: Dont click the stpid link below its malware

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The length of a side of a cubical box is 45 m.Find its volume

Harlamova29_29 [7]

Step-by-step explanation:

Since the box is a cube,

Length = Width = Height = 45m.

Volume of box = Volume of cube

= Length x Width x Height

$= 45 \times 45 \times 45 \\ = 91125 {m}^{3}$

8 0

3 years ago

A central angle theta in a circle of radius 7 m is subtended by an arc of length 8 m. Find the measure of theta in degrees. (Rou

gogolik [260]

Answer: In degrees , The measure of $\theta=65.5^{\circ}$

In radians , the measure of $\theta =\dfrac{8}{7}\text{ radians}$ .

Step-by-step explanation:

We know that the formula for length of arc is given by :-

$l=\theta r$

, where $\theta$ = Central angle subtended by arc.

r= radius of the circle.

As per given , we have

Radius of circle : r=7 m

Length of arc : l= 8 m

Substitute these values in the above formula , we get

$8=\theta (7)\\\\\Rightarrow\ \theta =\dfrac{8}{7}\text{ radians}$

Hence, the measure of $\theta =\dfrac{8}{7}\text{ radians}$ .

To convert it into degrees we multiply it with $\dfrac{180^{\circ}}{\pi}$

The measure of $\theta =\dfrac{8}{7}\times\dfrac{180^{\circ}}{\pi}$

$=(\dfrac{8\times180}{7\times3.14})^{\circ}=65.5141037307^{\circ}$

$\approx65.5^{\circ}$

Hence, the measure of $\theta=65.5^{\circ}$

8 0

3 years ago

The figure shows the location of 3 points around a lake. The length of the lake, BC, is also shown.

lions [1.4K]

Answer:

5.29

Step-by-step explanation:

Pythagorean theorem is used

We will call AB x

x^2 + 6^2 = 8^2

x^2 + 36 = 64

x^2 = 28

x = 5.2915026

4 0

3 years ago

2. A dance floor is a square with an area of 1,444 FT(2). What are the dimensions of the dance floor?

svet-max [94.6K]

Answer:

The answer is C use a calculator

Step-by-step explanation:

not that hard lol

8 0

3 years ago

Write the quadratic equation whose roots are 2 and -4 and whose leading coefficient is 2

Goryan [66]

Answer:

2x^2+4x-16

Step-by-step explanation:

The quadratic can be written as

f(x) = a(x-z1)(x-z2) where z1 and z2 are the roots

f(x) = a (x-2)(x- -4)

a is the leading coefficient

f(x) = 2(x-2)(x+4)

= 2(x^2 -2x+4x-8)

= 2(x^2 +2x-8)

= 2x^2 +4x-16

5 0

3 years ago