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amm1812
3 years ago
15

The school cafeteria buys bottles of water for $0.75 each and sells them for $1.05 each. By what percentage does the cafeteria m

arkup the price of water bottles? Do NOT include units or percent signs!
Mathematics
1 answer:
ehidna [41]3 years ago
7 0

Answer:

40

Step-by-step explanation:

Cost of the bottles of water = $0.75

Sales of the bottle= $1.05

markup Price= [(Sales of the bottle)-(Cost of the bottles of water)]/Cost of the bottles of water

= ($1.05- $0.75)/$0.75

= $0.30/$0.75

=0.40×100%

40%

=

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0% probability that the mean of the sample taken is less than 2.2 feet.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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This means that \mu = 2.5, \sigma = 0.2

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Z = \frac{X - \mu}{s}

Z = \frac{2.2 - 2.5}{\frac{0.2}{\sqrt{41}}}

Z = -9.6

Z = -9.6 has a p-value of 0.

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