Answer:
d=117.33 m
Step-by-step explanation:
Initial velocity of planes, u = 0 (because they are at rest)
Acceleration, a = 3.3 m/s²
Final take off speed, v = 88 m/s
We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

Putting all the values, we get :

Hence, the minimum allowed length for the runway is 117.33 m.
The answer is 600
25 x 4 =100
150 x 4 = 600
checking work
.25 x 600= 150
Answer: 7x^2-8x+10
Step-by-step explanation: hope this helps gl :)
thx for the points
Answer:
21 5/9
Step-by-step explanation: