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mihalych1998 [28]
3 years ago
13

Multiply 6x 10 by 12,2

Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

Huh??

Step-by-step explanation:

6x10=60/12=5×2=10??????

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5x+y=-10 4x-7y=-8 Substition Method (Show it step by step please!)
Fynjy0 [20]

\left\{\begin{array}{ccc}5x+y=-10&|\text{subtract 5x from both sides}\\4x-7y=-8\end{array}\right\\\left\{\begin{array}{ccc}y=-5x-10&|\text{substitute to the second equation}\\4x-7y=-8\end{array}\right\\\\4x-7(-5x-10)=-8\qquad\text{use distributive property}\\\\4x+(-7)(-5x)+(-7)(-10)=-8\\\\4x+35x+70=-8\qquad\text{subtract 70 from both sides}\\\\39x=-78\qquad\text{divide both sides by 39}\\\\\boxed{x=-2}\\\\\text{Put the value of x to the first equation}\\\\y=-5(-2)-10\\\\y=10-10\\\\\boxed{y=0}

Answer:\ \boxed{x=-2\ and\ y=0}

3 0
3 years ago
Read 2 more answers
A lighthouse casts a 128-ft shadow. A nearby lamppost that measures 5
olga nikolaevna [1]

Answer: 80 feet

Step-by-step explanation:

We can write these as fractions and do cross multiplication with the numerator being the height of the object while the denominator being the length of the shadow:

5 * 128 = 8x

640 = 8x

80 = x

Thus, the height of the lighthouse is 80 feet tall.

8 0
3 years ago
What is the elasped time 9:00- 4:30
LuckyWell [14K]
12-9=3

3+12+4,5=19,5

19 hours and 30 min
8 0
3 years ago
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Help Me With This Show Work If You Want
puteri [66]
Use the Pythagorean therm , you know the a^2+b^2=c^2 
8 0
3 years ago
A guitar string is plucked at a distance of 0.6 centimeters above its resting position and then released, causing vibration. The
liubo4ka [24]

Answer:

The equation that represents the motion of the string is given by:

y =Ae^{-kt}\cos(2\pi ft)     .....[1] where t represents the time in second.

Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.

Substitute the given values in [1] we get;

y =0.6e^{-1.8t}\cos(2\pi 105t)  

or

y =0.6e^{-1.8t}\cos(210\pi t)  

(a)

The trigonometric function that models the motion of the string is given by:

y =0.6e^{-1.8t}\cos(210\pi t)

(b)

Determine the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24

Using graphing calculator for the equation

y =0.6e^{-1.8x}\cos(210\pi x)

let x = t (time in sec)  

Graph as shown below in the attachment:

we get:

the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24 is, 0.5 sec


4 0
3 years ago
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