A = 1/2bh, where A is the surface area and b is the base, and H is the height.

Point M is located at (4,6) on a coordinate grid. Point M is translated 8 units to thr left and 9 units down to create point M'.

nata0808 [166]

Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!

We have the point 4,6. 4 is the x, and 6 is the y.

Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.

Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.

So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!

The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²

Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.

So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.

So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²

Solving it out, we first need to work within the parenthesis. Can you solve it?

Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²

8²= 64
9²= 81

64+81 = 145.

So, the distance between point M and point M' would be 145 units

Hope this helps!

If it does not, please let me know so i can try to help!

4 0

3 years ago

HELP!!! CORRECT ANSWER NEEDED OR ELSE I FAIL ;-; STUDY ISLAND !!

Ket [755]

Answer:

B. Step 2 uses the associative property, and step 3 uses the commutative property.

Step-by-step explanation:

The associative property lets you group terms for addition any way you like. It appears that in Step 2, the grouping is ...

4 + (1/6 + 3) + 5/6

The commutative property lets you change the order of any pair of terms involved in addition. It appears that in Step 3, the order of the terms within the group has been swapped.

4 + (3 + 1/6) + 5/6

_____

Comment on associative and commutative properties

What applies to terms in addition applies to factors in multiplication.

5 0

2 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

║

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

⊥

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

║

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

6 0

3 years ago

Type an equation of the given in the form y=A sin Bx or y=A cos Bx. pls pls I need help

galina1969 [7]

Woahhhh that looks hardddd

5 0

2 years ago

Describe some main differences between an Euler graph and a tree graph.

posledela

Answer:

The Obvious

Euler graph all connects almost like a circle

A tree graph looks like it branches off each other with no line connect in a circle like form

3 0

3 years ago