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erastova [34]
3 years ago
9

Which auto insurance coverage pays for injury or damage that the insured driver causes to other people or their property?

Mathematics
2 answers:
ivann1987 [24]3 years ago
5 0

Answer:

Auto Liability Insurance

Step-by-step explanation:

Auto Liability insurance can be defined as the car insurance that covers or protects the insured person from any lawsuits that could arise due to any accident that was caused by the insured person which led to bodily injuries or damages of another person's properties.

Liability insurance comes in two forms

a. Bodily injury liability coverage: This is helps the insured person to be to pay the medical fees of the injured person involved in the accident caused by the insured person

b. Property Damage liability coverage:

This is an type of auto liability insurance that helps the insured person pay for car repairs of the other person involved in the accident that was caused by the insured person.

It is advisable that most car owners ensure that both the bodily injury liability coverage and the property damage liability coverage are present in auto liability insurance package that they decide to get.

pashok25 [27]3 years ago
3 0

Bodily injury liability and property damage liability is the auto insurance coverage that pays for injury or damage that the insured driver causes to other people or their property

To add, bodily injury liability also provides a legal defense in the event that you are sued for damages. Also, property damage liability<span> <span>coverage helps pay for the </span></span>damage<span> <span>that you cause to another vehicle, or other types of </span></span>property<span>.<span> </span></span>

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The area of the entire figure below is 111 square unit.
Ivahew [28]

The striped rectangle has a total area of 69,375 cm².

<h3>How to calculate the area of the striped rectangle?</h3>

To find the area of the striped rectangle we must carry out the following procedures.

Find the area of each segment of the rectangle, that is, what is the area of each of the 24 squares that make up the rectangle, for that we divide the 111cm² of the total area into 24.

  • 111cm² ÷ 24 = 4.625cm²

According to the above, we infer that each square has an area of 4.625cm².

On the other hand, to find the area of the striped rectangle we must take into account that it is 5 squares long by 3 squares high, that is, its area is 15 squares.

  • 3 × 5 = 15

Finally, each square has an area of 4.625cm², so to find the total area of the striped area we must multiply the area of each square by the number of squares.

15 × 4.625cm² = 69.375cm²

Learn more about areas in: brainly.com/question/27683633

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7 0
2 years ago
45<br> as a product of prime factors
Darya [45]
3*3*5 is equal to 45 AND its factors are prime.

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5 0
3 years ago
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10 POINTS. I WILL MARK BRAINLIEST 
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1. BC = 9 tan 45 = 9 ft
AC = 9 tan 60 = 9 sqrt(3) ft
AB = AC - BC = 9sqrt3 - 9 ft ~ 6.59 ft

2. G-Zoo = 200sqrt3 / tan 60 = 200 ft
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Zoo-Library = G-Library - G-Zoo = 600 - 200 = 400 ft
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3 years ago
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Each year, more than 2 million people in the United States become infected with bacteria that are resistant to antibiotics. In p
Olegator [25]

Answer:

Reject <em>H</em>₀. There is a significant difference in drug resistance between the two states.

Step-by-step explanation:

In this case we need to determine whether the data suggest a statistically significant difference between the proportions of drug-resistant cases in the two states.

The significance level of the test is, <em>α</em> = 0.02.

(1)

The hypothesis can be defined as follows:  

<em>H</em>₀: There is no difference between the proportions of drug-resistant cases in the two states, i.e. p_{1} - p_{2}=  0.  

<em>Hₐ</em>: There is a statistically significant difference between the proportions of drug-resistant cases in the two states, i.e. p_{1} - p_{2}\neq  0.  

(2)

Compute the sample proportions and total proportion as follows:

\hat p_{1}=\frac{12}{189}=0.063\\\\\hat p_{2}=\frac{8}{429}=0.019\\\\\hat p=\frac{12+8}{189+429}=0.032\\

Compute the test statistic value as follows:

Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat p(1-\hat p)\times [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

   =\frac{0.063-0.019}{\sqrt{0.032(1-0.032)\times [\frac{1}{189}+\frac{1}{429}]}}\\\\=2.86

The test statistic value is 2.86.

(3)

The decision rule is:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

Compute the p-value as follows:

p-value=2\cdot P(Z>2.86)=2\times 0.00212=0.00424

<em>p</em>-value = 0.00424 < <em>α</em> = 0.02.

The null hypothesis will be rejected at 0.02 significance level.

Reject <em>H</em>₀. There is a significant difference in drug resistance between the two states.

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Simplify the expression shown below.(6+8i)(4-7i)

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