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frozen [14]
2 years ago
6

Write a C++ function with the following signature: void readAndConvert() The function takes no parameters and returns no value.

Instead, it reads its input from std::cin and writes its output to std::cout. Both the input and output are information describing a sequence of stock trades, albeit in different formats. Input format The input will be formatted according to the following specification. You may freely assume that the input will be in the format described here; it doesn't matter what your function does with input that doesn't meet those requirements. • The first line of the input will contain a positive integer, which will specify the number of trades whose information will be present in the input. • The second line of the input will contain the stock's symbol, which is a sequence of uppercase letters. • The third line of the input will contain a brief description of the stock, which is any arbitrary sequence of characters. • After that will be one line for each trade - so the integer on the first line tells you how many more lines there will be — which will contain three pieces of information separated by spaces! • A positive integer specifying the number of shares traded. o The price paid for each share, which is a number that will always have exactly two digits after the decimal point. • A sequence of lowercase letters that specifies a confirmation number for the trade. One example input that follows that format is as follows, though your function would need to work on any input that follows the specification, not just the one example. BOO Forever Boo Enterprises 100 50.00 barzxfq. 200 60.75 hhpncstvz 150 7.90 cjjm 175 100.15 fryzyt Output format Your function's output is a reorganization of the information from the input, which you would write in the following format. • The first line of output would contain the description of the stock, followed by a space, followed by the symbol surrounded by parentheses. • Each subsequent line of output describes one of the trades from the input, in the following format: o The confirmation number, followed by a colon and a space, followed by the integer number of dollars spent in the order (i.e., the number of shares times the price per share, always rounding to the floor of the number). The correct output for the example input above is as follows. Forever Boo Enterprises (BOO) barzxfq: 5000 hhpncstvz: 12150 cjjm: 1185 fryzyt: 17526 It is irrelevant whether your program prints all of the output only after reading the input, or whether it prints the output while it reads input; this is your choice. The only requirement is that your output meets the formatting requirements.
Computers and Technology
1 answer:
shepuryov [24]2 years ago
4 0

Answer:

The function is as follows:

void readAndConvert(){

   int n; string symbol,name;

   cin>>n;

   cin>>symbol;

   cin.ignore();

   getline (cin,name);

   vector<string> trades;

   string trade;

   for (int inps = 0; inps < n; inps++){

       getline (cin,trade);

       trades.push_back(trade);}

   

   cout<<name<<" ("<<symbol<<")"<<endl;

   for (int itr = 0; itr < n; itr++){

       string splittrade[3];        int k = 0;

       for(int j=0;j<trades.at(itr).length();j++){

           splittrade[k] += trades.at(itr)[j];

           if(trades.at(itr)[j] == ' '){

               k++;    }}

cout<<splittrade[2]<<": "<<floor(stod(splittrade[1]) * stod(splittrade[0]))<<endl;        }

   }

Explanation:

See attachment for complete program where comments are used to explain each line

Download cpp
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Description
lapo4ka [179]

Answer:

from datetime import time, datetime, timedelta, date

for _ in iter(list, 0):

   t1 = input("Please enter time one: ")

   t2 = input("Please enter time two: ")

   if t1.isdigit() == True and (int(t1[:2])<=23 and int(t1[2:]) <= 59)\

       and t2.isdigit() == True and (int(t2[:2])<= 23 and int(t2[2:])<=59):

       time_1 = time(hour=int(t1[:2]), minute=int(t1[2:]))

       time_2 = time(hour= int(t2[:2]), minute=int(t2[2:]))

       if time_1 > time_2:

           diff = datetime. combine (date. today( ), time_1) - datetime. combine(date. today ( ), time_2)

       else:

           diff = datetime. combine (date. today( ), time_2) -datetime. combine(date. today ( ), time_1)

       diff_list = str(diff).split(":")

       del diff_list[2]

       diff_t = "". join (diff_list)

       print(diff_t)

       break        

   if t1.isdigit() == False or t2.isdigit() == False:

       print("Military Time Forest Required: Bad input, try again.")

       continue

   elif int(t1[:2])> 23 or int(t2[:2])> 23:

       print("Military Tine Format Required: Hours must be between 00 and 23, try again")

       continue

   elif int(t1[2:])> 59 or int(t2[2:])> 59:

       print("Military Tine Format Required: Minutes must be between me and 59, try again")

       continue

Explanation:

The python Datetime package is used to manipulate date and time, creating immutable Datetime objects from the various python data types like integer and string. The block of code above is a conditional for-loop statement that gets two user time value inputs and prints out the difference as a string in Military forest time format.

5 0
3 years ago
The readline method reads text until an end of line symbol is encountered, how is an end of line character represented
zhannawk [14.2K]

Answer:

\n

Explanation:

readline() method is used to read one line from a file. It returns that line from the file.    

This line from the file is returned as a string. This string contains a \n at the end which is called a new line character.

So the readline method reads text until an end of line symbol is encountered, and this end of line character is represented by \n.

For example if the file "abc.txt" contains the lines:

Welcome to abc file.

This file is for demonstrating how read line works.

Consider the following code:

f = open("abc.txt", "r")  #opens the file in read mode

print(f.readline()) # read one line from file and displays it

The output is:

Welcome to abc file.    

The readline() method reads one line and the print method displays that line.                        

3 0
3 years ago
If an if- else statement is true, it will include which kinds of results?
Salsk061 [2.6K]

In an if...else statement, if the code in the parenthesis of the if statement is true, the code inside its brackets is executed. But if the statement inside the parenthesis is false, all the code within the else statement's brackets is executed instead.

Of course, the example above isn't very useful in this case because true always evaluates to true. Here's another that's a bit more practical:

#include <stdio.h>

int main(void) {

int n = 2;

if(n == 3) { // comparing n with 3 printf("Statement is True!\n");

}

else { // if the first condition is not true, come to this block of code

printf("Statement is False!\n"); } return 0;

}

Output:

Statement is False!

5 0
3 years ago
Can you help me in this question
Amiraneli [1.4K]

Answer:

6 2 and 0

Explanation:

This algorithm doesn't work if the list is not ordered ascending.

In this example it is not, and indeed the item "1" is never found.

first cycle: first=0, last=12 so midpoint=6

second cycle: first=0, last=5 so midpoint=2

last cycle: first=0, last=1 so midpoint=0

then last is assigned -1 so the while statement is no longer true.

7 0
3 years ago
What is one current method of detecting planets orbiting around other stars?
Gnoma [55]
C

D is the old way.

A they have not done yet

B not even a thing
5 0
3 years ago
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