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Ber [7]
3 years ago
13

4. What is the connection between productivity and Microsoft Office/ Office 365?

Computers and Technology
1 answer:
ikadub [295]3 years ago
3 0
Microsoft 365 plans for home and personal include the robust Office desktop apps that you're familiar with, like Word, PowerPoint, and Excel. ... Office 2019 is sold as a one-time purchase, which means you pay a single, up-front cost to get Office apps for one computer.

Hope this helps :)
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Which term refers to a fact that naturally occurs in the universe?
MrMuchimi

Answer: a scientific law

Explanation:

8 0
3 years ago
Read 2 more answers
Let A and B be two stations attempting to transmit on an Ethernet. Each has a steady queue of frames ready to send; A’s frames w
Mariana [72]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete and correct question in the attachment file.  

For Point a:

For the second round,

A is selects kA(2)  either 0 or 1, so for each of them, that is \frac{1}{2}.

B selects kB(2)\  from\  (0, 1, 2, 3) for each choice with the probability of \frac{1}{4}.

If kA(2) < kB(2) wins the second rear race.

\to P[A \ wins] = P[kA(2) < kB(2)]

                     = P[kA(2) = 0] \times P[kB(2) > 0] + P[kA(2) = 1] \times P[kB(2) > 1]\\\\= \frac{1}{2} \times \frac{3}{4}  + \frac{1}{2}  \times \frac{2}{4} \\\\=\frac{3}{8}  +\frac{2}{8} \\\\= \frac{3+2}{8}\\\\= \frac{5}{8}

For Point b:

Throughout this example, kA(3) also selects to be either 0 or 1 with such a \frac{1}{2} probability. So, although B chooses kB(3) from (0, 1, 2, 3, 4, 5, 6, 7), the probabilities each are \frac{1}{8}:

\to P[A \  wins] = P[kA(3) < kB(3)]

                     = P[kA(3) = 0] \times P[kB(3) > 0] + P[kA(3) = 1] \times P[kB(3) > 1]\\\\= \frac{1}{2} \times \frac{7}{8} + \frac{1}{2} \times \frac{6}{8}\\\\= \frac{7}{16} + \frac{6}{16}\\\\= \frac{7+6}{16} \\\\= \frac{13}{16}\\\\

For point c:

Assume that B tries again 16 times (typical value), and it destroys. In addition, throughout the exponential background n is obtained at 10 when choosing k between 0 to 2n−1. The probability of A winning all 13 backoff events is: P[A \text{wins remaining races}] = 16\pi i =4P[A \ wins \ i |A \ wins \ i -1 ]

Let the k value kA(i) be A for the backoff race I select. Because A retains the breed

=(kA(i)] \cdot P[kA(i+ 1)< kB(i+ 1)] \geq P[kA(i) + 1

For point d:

Two stations A and B are supposed. They assume that B will try 16 times afterward. Even so, for A, 16 races were likely to also be won at a rate of 0.82 For Just higher expectations of three A, B, and C stations. For Station A, possibility to win all backoffs

3 0
3 years ago
What is TLB for? Why TLB? Given the following number, what is theeffective memory access time?
vodomira [7]

Answer:

A lookaside buffer translation (TLB) is a memory cache that reduces the time it takes to access a user memory place. TLB includes the most lately used page table entries.

TLB is used to overcome the issue of sizes at the time of paging. Page Table Entry (PTE) is used for framing the memory ,but it uses two references one for finding  the frame number and the other for the address specified by frame number.

<u>Formula for finding effective memory access time-</u>

Effective Memory Access Time = (TLB access_time+Memory Access Time)*hit ratio + (TLB access_time+2*Memory Access Time)*(miss ratio)

Given in question,

Hit ratio = 0.90

Memory Access Time = 150ns

TLB access time= 5ns

Effective Memory Access Time = (TLB access_time+Memory Access Time)*hit ratio + (TLB access_time+2*Memory Access Time)*(miss ratio)

                            =(5+150) * 0.90 + (5+2*150)*(1-0.90)

                             =155 * 0.90 + (305*0.1)

                             =139.5 + 30.5

                             = 170ns

8 0
3 years ago
Using a WHILE loop write a program that asks the user to guess your favorite number. The program should end when the user guesse
eduard

Answer:

fav_number=26

guess=0

while 0==0:

   try:

       guess=int(input('Enter your guess: '))

   except:

       print ('You have entered an invalid value.')

   else:

       if guess == fav_number:

           break

       elif guess>fav_number:

            print ('Try a smaller number.')

       elif guess<fav_number:

           print ('Try a larger number')

Explanation:

define a variable fav_number and set it to number. write an infinite while loop to read input from user. In try block get input from user, if user enters invalid input code in except block will be executed. For valid input

  1. check if its greater than favorite number, if yes print try smaller number.
  2. check if its smaller than favorite number, if yes print try larger number.
  3. check if its equal to favorite number, break loop and exit

4 0
4 years ago
This goes to all of my friends who posted the "oh no i accidentally" questions lolll
bija089 [108]
Well thank you I think
6 0
3 years ago
Read 2 more answers
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