Answer:
true
Explanation:
there are a lot of easier ways to access clients through computers with the internet.
A barcode's bars have
1. different thicknesses, so they each signify 1 or 2 nibbles.
2. the combinations of the thicknesses of those bars exceed the trillions. That's why manufacturers and stores never run out of SKU barcodes.
Answer:
Explanation:
Following are the Semaphores:
Customers: Counts waiting customers;
Barbers: Number of idle barbers (0 or 1)
mutex: Used for mutual exclusion.
Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves
Shared data variable:
count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.
// shared data
semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;
int count_cust= 0;
void barber() {
while(true) { //shop is always open
wait(customers); //sleep when there are no waiting customers
wait(mutex); //mutex for accessing customers1
count_cust= count_cust-1; //customer left
signal(barbers);
signal(mutex);
cut_hair();
}
}
void customer() {
wait(mutex); //mutex for accessing count_cust
if (count_cust< n) {
count_cust= count_cust+1; //new customer
signal(customers); signal(mutex);
wait(barbers); //wait for available barbers get_haircut();
}
else { //do nothing (leave) when all chairs are used. signal(mutex);
}
}
cut_hair(){ waiting(cutting);
}
get_haircut(){
get hair cut for some time; signal(cutting);
}
Answer:
Runs code line by line to help developers find bugs.
Explanation:
I took the test.
Answer:
The statement is as follows:
cout <<fixed<< setprecision(3) <<sales;
Explanation:
Here, I assume that the variable has already been declared.
The syntax to use is:
cout<<fixed<<setprecision(n)<<variable-name;
In this case:
--- i.e. to 3 decimal places
And the variable name is: sales
So, when implemented, the instruction is:
cout <<fixed<< setprecision(3) <<sales;
