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user100 [1]
3 years ago
5

PLEASE ANSWER RN!! Which statement can be represented by the equation Two-fifths x + 9 = 9? Two-fifths of nine is a number. Two-

fifths of a number is nine. Nine more than two-fifths of a number is nine. A number plus nine is the same as two-fifths of nine.
Mathematics
2 answers:
nadezda [96]3 years ago
7 0

Answer:

Step-by-step explanation:

(2/5)x + 9 = 9 is equivalent to (2/5)x = 0

"Nine more than two-fifths of a number is nine" is correct.

Nitella [24]3 years ago
6 0

Answer:

Nine more than two-fifths of a number is nine

Step-by-step explanation:

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almond37 [142]

Answer:

190.67 ft/sec

Step-by-step explanation:

130 mi/hr x 5280 ft/mi x 1/60 hr/min x 1/60 min/sec = 190.67 ft/sec

It makes more sense if you write these as fractions and cancel units.

5 0
3 years ago
Esi says that the value of z when z^2 = 80 does not belong in either of these categories since z must be greater than 8.
Anettt [7]

Answer:

9

Step-by-step explanation:

if z=8 then z^2 would be 64, which is not equal to 80

iz z=9 then z^2 would be 81, which is closer to 80 than 64

therefore, 9 is the whole number than z would be closest to

7 0
2 years ago
Read 2 more answers
I'm Confused Could Anyone Help me
Sliva [168]
C d e are correct...hope this helps
4 0
3 years ago
Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

5 0
3 years ago
Write the point slope form of the given line that passes through points (-4,-1) and (3,-3). Identify (x1,y1) as (-4,-1) include
Masteriza [31]
Y-y1=m(x-x1)

find slope
(y2-y1)/(x2-x1)

so
(-4,-1)
(3,-3)
slope=(-3-(-1))/(3-(-4))=(-3+1)/(3+4)=-2/7

y-(-1)=-2/7(x-(-4))
y+1=-2/7(x+4)
6 0
3 years ago
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