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Gwar [14]
1 year ago
8

A television is on sale for 25% off the regular

Mathematics
1 answer:
zlopas [31]1 year ago
8 0

Answer:

Step-by-step explanation:

First subtract $339.95 by 25% which will equal $254.96525. Then add 15% by $254.96525 which will equal $293.206875. And always remember to round up.

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Try factoring this before moving on: 25+10x+x^2
Naddika [18.5K]

Answer:

Step-by-step explanation:

x2 + 10x + 25

x2 + 5x + 5x + 25

x (x + 5) + 5(x + 5)

(x + 5) (x + 5)

4 0
3 years ago
If you don’t know I don’t answer (NO LINKS ) please helllllppppp
Marina CMI [18]

Answer:

Step-by-step explanation:

1. 6.96 in

2. 2.6 in

3. 8.1 in

4. 5.6 m

5. 1.89 cm

6. 6 in

6 0
3 years ago
What is the shaded portion of the circle
blagie [28]

Answer:

(5\pi-11.6)\ ft^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector minus the area of the triangle

step 1

Find the area of the circle

the area of the circle is equal to

A=\pi r^{2}

we have

r=5\ ft

substitute

A=\pi (5)^{2}

A=25\pi\ ft^{2}

step 2

Find the area of the sector

we know that

The area of the circle subtends a central angle of 360 degrees

so

by proportion find out the area of a sector by a central angle of 72 degrees

\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}

step 3

Find the area of triangle

The area of the triangle is equal to

A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}

step 4

Find the area of the shaded region

Subtract the area of the triangle from the area of the sector

(5\pi-11.6)\ ft^{2}

8 0
2 years ago
Is this perpendicular, parallel, or neither?<br>y=4x+5 <br>2x+8y=16
ANEK [815]
Its perpendicular, if you need me to explain lmk
6 0
3 years ago
The value of x satisfying both the equations 4x – 5 = y and 2x – y = 3, when y = -1 is
schepotkina [342]

Answer:

x = 1

Step-by-step explanation:

4x-5=y

4x-5= -1

4x = -1+5

4x=4

x=1

2x-y=3

2x-(-1)=3

2x+1=3

2x= 3-1

2x= 2

x=1

since the two answers for x are the same therefore:

x = 1

4 0
3 years ago
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