Answer:
Total eclipse was 
minutes longer than in 2005.
Step-by-step explanation:
It is given in the question that total eclipse in 2003 lasted 
minutes and in 2005 it lasted 3/8 of a minute.
We have to calculate how much longer did it last in 2003.
So we have to subtract the duration in 2003 by duration in 2005
Total time taken in 2003- total time taken in 2005
minutes
Answer:
27 chickens
Step-by-step explanation:
A chicken farmer also has cows for a total of 30 animals
Both animals have a total of 66 legs
Let a represent the number of chicken
Let b represent the number of cows
a + b= 30........equation 1
Since a chicken has only two legs and a cow has four leg then, the expression can be represented as
2a + 4b= 66........equation 2
From equation 1
a + b= 30
a = 30-b
Substitute 30-b for a in equation 2
2a + 4b= 66
2(30-b) + 4b= 66
60 - 2b + 4b= 66
60 + 2b= 66
2b= 66-60
2b= 6
b= 6/2
b= 3
Substitute 3 for b in equation 1
a + b = 30
a + 3=30
a= 30-3
a= 27
Hence the farmer has 27 chickens
<span>For any angle between 0° and 180°, the supplement of <em>the angle</em> is 180° – <em>the angle.</em></span>
<span><em>=> </em>180-179=1</span>
<span>So the supplement of 179 is 1.</span>
<span><em /></span><span>
</span>
Use the geometric mean for right triangles here. Like this
. Cross multiply to get
, and
. That simplifies down to
. Pull out the 9 as a perfect square of 3 and you're left with
, first choice above.
We know that
if ∠WCR=49°
then
measure arc WR=49°-------> by central angle
circumference C=2*pi*r
for r=7 in
C=2*pi*7-----> 43.96 in
if 360°(full circle) has a length of----------> 43.96 in
49°---------------> x
x=49*43.96/360-----> x=5.98 in
alternative method
applying the formula
L=(∅/360°)*2*pi*r
where
∅ is the angle in degrees
r is the radius
L=(49°/360°)*2*pi*7------> L=5.98 in
the answer is
5.98 in
