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drek231 [11]
3 years ago
6

I need the answer fast pls

Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Answer:

C. 15

Step-by-step explanation:

You just need to add the number of dots, hoped this helped and was fast enough

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Ber [7]

Refer to this previous solution set

brainly.com/question/26114608

===========================================================

Problem 4

Like the three earlier problems, we'll place the kicker at the origin and have her kick to the right. The two roots in this case are x = 0 and x = 20 to represent when the ball is on the ground.

This leads to the factors x and x-20 and the equation y = ax(x-20)

We'll plug in (x,y) = (10,28) which is the vertex point. The 10 is the midpoint of 0 and 20 mentioned earlier.

Let's solve for 'a'.

y = ax(x-20)\\\\28 = a*10(10-20)\\\\28 = -100a\\\\a = -\frac{28}{100}\\\\a = -\frac{7}{25}\\\\

This then leads us to:

y = ax(x-20)\\\\y = -\frac{7}{25}x(x-20)\\\\y = -\frac{7}{25}x*x-\frac{7}{25}x*(-20)\\\\y = -\frac{7}{25}x^2+\frac{28}{5}x\\\\

The equation is in the form y = ax^2+bx+c with a = -\frac{7}{25}, \ b = \frac{28}{5}, \ c = 0

The graph is below in blue.

===========================================================

Problem 5

The same set up applies as before.

This time we have the roots x = 0 and x = 100 to lead to the factors x and x-100. We have the equation y = ax(x-100)

We'll use the vertex point (50,12) to find 'a'.

y = ax(x-100)\\\\12 = a*50(50-100)\\\\12 = -2500a\\\\a = -\frac{12}{2500}\\\\a = -\frac{3}{625}\\\\

Then we can find the standard form

y = ax(x-100)\\\\y = -\frac{3}{625}x(x-100)\\\\y = -\frac{3}{625}x*x-\frac{3}{625}x*(-100)\\\\y = -\frac{3}{625}x^2+\frac{12}{25}x\\\\

The graph is below in red.

4 0
3 years ago
The area of a square garden is 50 m3. How long is the diagonal?
katen-ka-za [31]

Answer:

10 m

Step-by-step explanation:

If the area of a square is 50 m2, then the length of each side will be \sqrt{50} m, to get the diagonal length, after dividing the square by joining the points of the diagonal with a line, it forms two right angles with length \sqrt{50} m each.

the diagonal length represent the hypotenuse side of each of the right angle, knowing the pythagoras theorem:

(hyp)^{2} = (opp)^{2}   + (Adj)^{2}, so we have:

(diagonal)^{2}  = 50 + 50

(diagonal)^{2}  = 100

diagonal = 10 m

6 0
3 years ago
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