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Goshia [24]
2 years ago
14

Find the distance represented by x

Mathematics
2 answers:
algol132 years ago
8 0

the distance of X is 180ft

trapecia [35]2 years ago
3 0
180

Explanation:
Set a equation of a ratio 120/90=x/135
And calculate!
90x=(120)(135)
90x=16200
x=180
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Solve the system of equations by graphing. Look at the picture. Will Mark Brainliest​
aleksandr82 [10.1K]

Answer:

See below

Step-by-step explanation:

<h3>Graphing:</h3>

we are given two functions

\displaystyle \begin{cases}f(x) =  - x + 5 \\ g(x) =  {x}^{2}   - 3x + 2\end{cases}

where f(x) is a <em>linear</em><em> </em><em>function</em> and g(x) is a <em>q</em><em>uadratic </em>function

we want to figure out the solutions of the function

let's graph f(x):

the Black-table is attached

let's graph g(x):

the picture is attached

hence, the graph should be

the graph is attached

<h3>solutions stating:</h3>

so we need solution(s) which satisfy(ies) the both functions

in this case the solution (s) the x coordinate(s) where both functions intercept we get from the graph that both functions intercept at <u>(</u><u>-</u><u>1</u><u>,</u><u>6</u><u>)</u> and <u>(</u><u>3</u><u>,</u><u>2</u><u>)</u>

hence,

x={-1,3}

5 0
3 years ago
Which list orders the numbers from least to greatest
DENIUS [597]
The second line
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2 years ago
PLEASE PELASE PLEASE HELP ME
V125BC [204]

Answer:

In ∆ABC AND ∆DEF

ABC=DEF...........each 90°

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3 0
2 years ago
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
3 years ago
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