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skad [1K]
3 years ago
14

Which expression is equivalent to -4(5x - 9) + 6(2x + 5)?

Mathematics
1 answer:
schepotkina [342]3 years ago
7 0

Answer:

-4(5x - 9) + 6(2x + 5)

multiplication of:

(-).(-) = +

(-).(+) = -

(+).(-) = -

(+).(+) = +

-4(5x) -4(- 9) + 6(2x + 5)

(-)(+)4(5x) (-)(-)4(9) (+)(+) 6(2x) (+)(+)6( 5)

-20x  + 36 + 12x + 30

-20x  + 12x + 36 + 30

-8x + 66

Step-by-step explanation:

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1 P   Parenthasis ()
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3 years ago
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BARSIC [14]
Divide because 40 divided by 8 is five

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8 0
3 years ago
Which line is parallel to line r?
zloy xaker [14]
S is parallel to line r

3 0
4 years ago
Read 2 more answers
One-half divided by three-fourths = StartFraction 1 Over a EndFraction times StartFraction b Over c EndFraction = StartFraction
lesya692 [45]

Answer:

A: 2

B:4

C:3

D:2

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
A. Use the​ one-mean t-interval procedure with the sample​ mean, sample​ size, sample standard​ deviation, and confidence level
PtichkaEL [24]

Answer:

a) (17.227, 22.773)

b) 2.773

c) 2.773

Step-by-step explanation:

Given:

Sample size, n = 25

Standard deviation, s = 4

Sample mean, x' = 20

Level of significance, a = 0.98 = 1 - 0.98 = 0.02

The degrees of freedom, df, for a t-distribution = n - 1 = 25 - 1 = 24

Using the t table, the Critical value = t_\alpha _/_2, _d_f = t_0_._0_2_/_2, _2_4 = t_0_._0_1_, _2_4 = 3.4668

Margin of error, E = t_\alpha _/_2, _d_f * \frac{\sigma}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

Limits of 98% confidence interval, we have:

Lower limit : x' - M.E = 20 - 2.773 = 17.227

Upper limit: x' + M.E = 20 + 2.773 = 22.773

Therefore, (17.227, 22.773) is 98% confidence interval.

b) Let's the margin of error by taking half the length of the confidence interval.

Since we are to use half the length of CI, we have:

M.E = \frac{22.773 - 17.227}{2} = 2.773

c)M.E = t_\alpha _/_2, _d_f *s/\sqrt{n}

= t * \frac{s}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

4 0
3 years ago
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