Solve for x. x/7+9=15 x=24 x=42 x=84 x=168

2 answers:

7 0

To solve an equation, you simply reverse the operations done to the variable you're trying to solve for.

We have the equation $\frac{x}{7}$ + 9 = 15

Currently, the x variable is being divided by 7 and added to 9.
We will need to reverse these operations to find the value of x.

And remember! Anything you do on one side of the equation, you must do on the other side.
We do this to keep the equation balanced.

Add can subtract 9 from each side of the equation.
That way on the left-hand side the 9 term will vanish.

$\frac{x}{7}$ + 9 - 9 = 15 - 9
$\frac{x}{7}$ = 6

Now for the final step. The x variable is being divided by 7.
What can we do to reverse that operation? In order words, what is the inverse of dividing something? Well, multiplying!

If we multiply each side by 7 we will get the value of x.

$\frac{x}{7}$ * 7 = 6 * 7
x = 42

So, x is equal to 42.

diamong [38]4 years ago

4 0

X=42

42/7+9=
6+9=
15

Hope this helps. :)

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2 years ago

Find the probability that a randomly selected person from this group voted for Oddems Family OR Thirteenth Night.

Masja [62]

Answer:

P(O∪T)= 0.92

Step-by-step explanation:

Hello!

The theater director offered every member of the drama one vote for which play they preferred to perform. The director found that 35% voted for "The Oddems Family", that 57% voted for "Thirteenth Night" and 8% did not vote.

You have three events with three associated probabilities:

O: The performer voted for Oddems Family. ⇒ P(O)= 0.35

T: The performer voted for the Thirteenth Night. ⇒ P(T)= 0.57

n: The performer did not vote. ⇒ P(N)= 0.08

In this group, are the events "Oddems Family" and "Thirteenth Night" mutually exclusive?

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in a single repeat of the trial, i.e. these two events cannot occur at the same time.

In this case, each performer has only one vote and can decide for either one of the plays, so if he votes for one, then he'll not vote for the other one. Then we can say that the events are mutually exclusive.

Find the probability that a randomly selected person from this group voted for "Oddems Family" or "Thirteenth Night"

You need to calculate the probability of a randomly selected performer to vote for either "Oddems Family" or "Thirteenth Night", this is a union between the two events and you can symbolize it as:

P(O∪T)

Remember:

Given the events A and B, that are mutually exclusive, you can calculate the union between them as:

P(A∪B)= P(A) + P(B)

Applying this to the exercise:

P(O∪T)= P(O) + P(T)= 0.35 + 0.57 = 0.92

I hope this helps!

8 0

3 years ago

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Sunny_sXe [5.5K]

$\large\text{Hey there!}$

$\large\text{Which expression is equivalent to 56?}$

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$\mathsf{ 6\times6\times6\times6\times6\times6\times6}\\\mathsf{6\times6=36}\\\mathsf{36\times6\times6\times6\times6\times6}\\\mathsf{36\times6=216}\\\mathsf{216\times6\times6\times6\times6}\\\mathsf{216\times6=1,296}\\\mathsf{1,296\times6\times6\times6}\\\mathsf{1,296\times6=7,776}\\\mathsf{7,776\times6\times6}\\\mathsf{7,776\times6= 46,656}\\\mathsf{46,656\times6=\bf{279,936}}\\\\\\\large\text{Option B. IS NOT our answer because its too big!}$