Answer:
1, 11x + 3y + 15z
2, 3x + 12y + -5z
Step-by-step explanation:
all you need to do is combined the like terms and make sure the signs (<em>positive and negative signs</em>) are right
Answer:varibale
Step-by-step explanation:
Answer: 8.9 units (choice C)
Explanation:
We plug
into the distance formula to get the following
![d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(7-(-1))^2 + (-1-3)^2}\\\\d = \sqrt{(7+1)^2 + (-1-3)^2}\\\\d = \sqrt{(8)^2 + (-4)^2}\\\\d = \sqrt{64 + 16}\\\\d = \sqrt{80}\\\\d \approx 8.94427\\\\d \approx 8.9\\\\](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_1%20-%20x_2%29%5E2%20%2B%20%28y_1%20-%20y_2%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%287-%28-1%29%29%5E2%20%2B%20%28-1-3%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%287%2B1%29%5E2%20%2B%20%28-1-3%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%288%29%5E2%20%2B%20%28-4%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B64%20%2B%2016%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B80%7D%5C%5C%5C%5Cd%20%5Capprox%208.94427%5C%5C%5C%5Cd%20%5Capprox%208.9%5C%5C%5C%5C)
<span>For all rectangles with a fixed perimeter of p the rectangle with the maximum area is one where the length is p/4 and the width is p/4, in other words a square. The area of such a rectangle would be (p*p) /16.</span>
Answer:
D.) c is multiplied by 4
Step-by-step explanation:
![c = \dfrac{8a^3}{b}](https://tex.z-dn.net/?f=%20c%20%3D%20%5Cdfrac%7B8a%5E3%7D%7Bb%7D%20)
If a is doubled, it becomes 2a. If b is doubled, it becomes 2b. Now we replace a with 2a and b with 2b and simplify.
![c = \dfrac{8(2a)^3}{2b}](https://tex.z-dn.net/?f=%20c%20%3D%20%5Cdfrac%7B8%282a%29%5E3%7D%7B2b%7D%20)
![c = \dfrac{8 \times 8a^3}{2b}](https://tex.z-dn.net/?f=%20c%20%3D%20%5Cdfrac%7B8%20%5Ctimes%208a%5E3%7D%7B2b%7D%20)
![c = \dfrac{4 \times 8a^3}{b}](https://tex.z-dn.net/?f=%20c%20%3D%20%5Cdfrac%7B4%20%5Ctimes%208a%5E3%7D%7Bb%7D%20)
![c = 4 \times \dfrac{8a^3}{b}](https://tex.z-dn.net/?f=%20c%20%3D%204%20%5Ctimes%20%5Cdfrac%7B8a%5E3%7D%7Bb%7D%20)
Answer: D.) c is multiplied by 4