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Ivenika [448]
2 years ago
11

a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi

nd the 95% confidense interval for the average length of a box. How many boxes do he need to measure to be accurate within 1 millimeters
Mathematics
1 answer:
vladimir1956 [14]2 years ago
8 0

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

You might be interested in
Find the measure of the exterior angle 1. with one angle is 50 degrees and 28 degrees​
OLga [1]

Answer:

D. 78°

Step-by-step explanation:

50°+28°= 78°

_______

3 0
3 years ago
Examine triangle ABC.<br><br> What is the value of x?<br><br> 37<br> 48<br> 127<br> 138
Flura [38]

The outside angle of B needs to equal 180 - 79 = 101 degrees.

The 3 outside angles of a triangle need to equal 360 degrees.

Set up the equation with what we know:

X + (x+5) + 101 = 360

Simplify:

2x + 106 = 360

Subtract 106 from both sides:

2x = 254

Divide both sides by 2:

x = 254 / 2

x = 127

4 0
2 years ago
Can someone please help me. It's for the elimination method.
mojhsa [17]
Since there is 101 Tickets, 
Let S + A = 101
1.50S + 2.50A = $186.50



Adults + Students = 101

$186. 50 = $2.50 Adults + $1.50 Students

Answer is 35 Adults, and 66 Students.




Hope that helps!!!
6 0
3 years ago
What is the first quartile
azamat
<span>The first quartile (Q1) is defined as the middle number between the smallest number and the median of the data set.</span>
8 0
3 years ago
Hurry please!!! Fast response
AlladinOne [14]

Answer:

A.

SA= \frac{2}{3} \pi rl+16 \pi r^2

Step-by-step explanation:

Surface area of the original cone

SA= \pi r l + \pi r^2... (1)

When, radius is quadrupled and slant height is reduced to one sixth

i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l

Plug the above values of r and l in equation (1), new surface area becomes:

SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2

SA= \frac{4}{6} \pi rl+16 \pi r^2

\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}

8 0
2 years ago
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