Answer: 12
Step-by-step explanation:
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
31
Step-by-step explanation:
it said 22 2's , so 22 + 9
and 0,1,3,4,5,6,7,8,9 is 9 numbers
1. 14.3-2*5²÷5=14.3-10=4.3
2. Result is Twenty one
Answer:
none of the given options is true
Step-by-step explanation:
Given: u=(-8,8) , v= (-1,2)
To find: vectors 
such that 
Solution:
A vector is a quantity that has both magnitude and direction.
Let 
So,
So, u = 
So, none of the given options is true
